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3 years ago

Plz help me due in 30min

Mathematics

2 answers:

bixtya [17]3 years ago

6 0

Answer:

$2.20

Step-by-step explanation:

$39.80/4= $9.95 per ticket

$46.50/6= $7.75 per ticket

$9.95-$7.75= $2.20 as your difference

I think this is right, I hope I helped!

IceJOKER [234]3 years ago

5 0

2.20 [•_•] Bc yeahhhh

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2 fraction bars. The first bar is labeled 1 with 5 boxes underneath that are labeled one-fifth. The second bar is labeled 1 with

GaryK [48]

Answer:

1 1 2

_ x _ = _ 2 divide by 25 =12.5

5 5 10

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Someone please explain step by step.

dolphi86 [110]

Answer:

${10}^{th} \: term = \frac{5}{512}$

Step-by-step explanation:

geometric progression formula:

${n}^{th} \: term = ar ^{n - 1}$

given:

common ratio, r = 1/2

$first \: term \: = 5$

1) find the value of a

${n}^{th} \: term \: = a {r}^{n - 1}$

we're finding the 1st term, so substitute 1 into n:

${1}^{st} \: term = a( \frac{1}{2} ) {}^{1 - 1}$

first term is 5. so we substitute 5 into the equation:

$5 = a(1)$

$a = 5$

2) find the 10th term

we're finding the 10th term, so substitute 10 into the equation and don't forget to substitute 5 into a:

${10}^{th} \: term = 5( \frac{1}{2} ) {}^{10 - 1}$

${10}^{th} \: term = 5( \frac{1}{512} )$

${10}^{th} \: term = \frac{5}{512}$

6 0

2 years ago

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Elenna [48]

Answer:

a) 4cd^2

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Step-by-step explanation:

5 0

2 years ago

If y is proportional to the sqaure root of x and y equal x when x equal 5,evaluate y when x eqaul 9.

Law Incorporation [45]

Answer:

$y = 3\, \sqrt{5}$ when $x = 9$ .

Step-by-step explanation:

The question states that $y$ is proportional to $\sqrt{x}$ . In other words, there is a constant $a$ ( $a \ne 0$ ) such that $y = a\, \sqrt{x}$ for all $x \ge 0$ .

The question also states that $y = x$ when $x = 5$ . Make use of this equality to find the value of $a$ .

Since $x = 5$ and $y = x$ , it must be true that $y = 5$ . Substitute $x = 5\!$ and $y = 5\!$ into the equation $y = a\, \sqrt{x}$ and solve for $a$ :