In the triangle ABC, the side lengths, in order from the greatest to the least, are : AC > AB > BC.
We are given a triangle. The vertices of the triangle are A, B, and C. The measures of the angles ∠A, ∠B, and ∠C are 36°, 84°, and 60°, respectively. We need to arrange the side lengths in order from the greatest to the least.
The side lengths are proportional to their opposing angles in a triangle. It means that the side opposite the largest angle is the largest side, and vice versa. The angles arranged in descending order are : 84° > 60° > 36°. The angles arranged in descending order according to the vertices are : B > C > A. The order of the lengths of the opposite sides must be the same.
Hence, the side lengths, in order from the greatest to the least, are : AC > AB > BC.
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Answer:
39=22
28-6 equal to 22 so 39= 22
rise over run
(-1,2) (2,2)
2-2/2-(-1)
2-2/2+1 equals 0/3
or alternatively
2-2/-1 - 2 which would be -0/3.
Whichever point is the first helps determine this alot
rise/run=rise over run= y2 - y1/ x2 - x1
Answer:
1/16
Step-by-step explanation:
Both 5 and 80 can be divided by 5.
This reduces the ratio of 5/80 to 1/16.
