Answer:
Step-by-step explanation:
a) edj
b) ed
c) i think ag
Answer:
14, 42
Step-by-step explanation:
Set A = {−7, −4, 2, 14, 21, 34, 42}
Set B = {even numbers}
Set C = {multiples of 7}
There is only one question asked
Which numbers in Set A are elements of both Set B and Set C,
We need it to be even and a multiple of 7
14 is even and a multiple of 7 and 42 is even and a multiple of 7
To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
Answer:61
Step-by-step explanation:
Z+Z-11=Z+50
2Z-11=Z+50
Collect like terms
2Z-Z=11+50
Z=61