Isn't this a subtraction problem, not a multiplication problem?
If John starts out with 20 fish and lets 6 go, he still has (20-6), or 14, fish.
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By the Pythagorean theorem
.. 15^2 = 10^2 +a^2
.. 225 = 100 +a^2
.. 125 = a^2
.. √125 = a
.. 5√5 = a ≈ 11.18
The missing side length is 5√5 cm.
Answer:
a) 2.5
b)2.33
Step-by-step explanation:
a)
Bring the numerals to the right hand side and the x terms to the left hand side
Simplify
Divide 3 on both sides, to get x
b)
Bring the numerals to the right hand side and the x terms to the left hand side
Simplify
9514 1404 393
Answer:
[[274][895][136]]
Step-by-step explanation:
Starting with the middle row, we need a product of two single-digit numbers that is between 53-1 = 52 and 53-9 = 44. Possible products are 5×9=45 and 6×8=48. This means the number in the middle position in the left column must be 8 or 5.
The middle number in the left column cannot be 5, because we must be able to get -5 by subtracting that number from a sum that is at least 3 = 1+2. So, the middle number in the left column is 8, the other two numbers in that column are 1 and 2, and the other two numbers in the middle row are 5 and 9.
There is no product of single-digit numbers that is 30-1 = 29, so the upper left number must be 2, and the bottom left number must be 1. The other two numbers on the top row must be 4 and 7, so that row's equation is 2+4×7=30.
The only remaining digits are 3 and 6. In order to have -3 on the bottom row, the equation there must be 1×3-6 = -3. Then the middle digit must be divisible by 3, so must be 9.
Our solution is ...
row 1: 2 + 7 × 4 = 30
row 2: 8 + 9 × 5 = 53
row 3: 1 × 3 - 6 = -3
And that makes the column equations be ...
col 1: 2 - 8 + 1 = -5
col 2: 7 + 9 / 3 = 10
col 3: 4 × 5 - 6 = 14
