Question

quiz 4-1 : classifying and solving for sides/angles in triangles gina wilson (all things algebra) URGENT

Answer 1

Answer:

14.

$x = 11$  $m$   $m$   $m$

15.

$x = 4$     $WX = 25$     $XY = 17$     $WY = 25$

Step-by-step explanation:

Solving (14):

$BC = BD$

$m$

$m$

$m$

First, we solve for x.

Since sides $BC = BD$, then

$m$

This is so because the theorem of ASA (Angle-Side-Angle)

So, we have:

$5x - 19 = 2x + 14$

Collect Like Terms

$5x - 2x = 19 + 14$

$3x = 33$

Divide both sides by 3

$x = 11$

Solving for m<B, m<C and m<D.

We simply substitute 11 for x in their respective expressions.

$m$

$m$

$m$

$m$

$m$

$m$

$m$

$m$

$m$

$m$

$m$

$m$

Solving (15):

$WX = 9x - 11$

$XY = 4x + 1$

$WY = 7x - 3$

First, we solve for x.

Since , then

$WX = WY$

This is so because the theorem of SAS (Side-Angle-Side)

So, we have:

$9x - 11 = 7x - 3$

Collect Like Terms

$9x - 7x = 11-3$

$2x = 8$

Divide both sides by 2

$x = 4$

Solving for WX, WY and XY

We simply substitute 4 for x in their respective expressions.

$WX = 9x - 11$

$WX = 9 * 4 - 11$

$WX = 36 - 11$

$WX = 25$

$XY = 4x + 1$

$XY = 4 * 4 + 1$

$XY = 16 + 1$

$XY = 17$

$WY = 7x - 3$

$WY = 7 * 4 - 3$

$WY = 28 - 3$

$WY = 25$