<h3>
Answer: 10^(1/2)</h3>
When we use an exponent of 1/2, it is the same as a square root. The more general rule is
In this case, we plug in x = 10.
The use of a fractional exponent is handy when you want to deal with things like cube roots on a calculator. This is because
![\sqrt[3]{x} = x^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3D%20x%5E%7B1%2F3%7D)
Many calculators don't have a button labeled ![\sqrt[3]{}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%7D)
but they have the button 
to allow fractional exponents.
X+2y=2 …(1)
x-2y=-2…(2)
(1)-(2): (x+2y)-(x-2y)=2- (-2)
4y=4
y=1
subs y=1 into(1)
x+2(1) =2
x=0
so x =0 y=1
the answer is C
Answer:
1g/25m
Step-by-step explanation:
divide both of them by 6 so one of them can be one
Please give me Brainliest
Translate the words into math and solve for x. Any questions let me know.
Answer:
d < 1
Step-by-step explanation:
First, we have to get d on the same side of the equation. So we will subtract d from both sides and the equation will be 12d-d < + 11. We could also write this problem as d(12-1) < 11, which when simplified would be d(11) < 11. Next, divide both sides by 11 and you get d< 1. Hope this helps and have a great day!!:D
