Find the exact length of the third side .

Quadrilateral FRIO is the result of a reflection of quadrilateral LAMB over the y-axis. FRIO has vertices at F(-7,6), R(1,7), I(

andrew11 [14]

Answer:

F' = (7, 6)

R' = (-1, 7)

I' = (-2, -5)

O' = (6, -6)

Step-by-step explanation:

The rule of reflection over the y-axis is, (x, y) ---> (-x, y). So change all the x values into the opposite signs. So the -7 of F would turn into just 7, the 1 of R would turn into -1, the 2 of I would turn into -2, and -6 of O would turn into just 6.

3 0

3 years ago

Triangle F G E is shown. Angle F E G is a right angle. The length of hypotenuse F G is 18.6 inches and the length of F E is 12 i

Delicious77 [7]

Answer:

Measure of ∠FGE is 40.2°.

Step-by-step explanation:

Refer to the attachment.

Consider ΔFGE. Given that ∠FEG = 90° and ∠FGE is x°.

To find the value of ∠FGE use trigonometric ratios.

Use sine ratio to find the value of ∠FGE.

$\sin \theta=\dfrac{opposite\:side}{hypotenuse\:side}$

Rewriting it in terms of x° as follows,

$\sin x=\dfrac{opposite\:side}{hypotenuse\:side}$

Now find the opposite and hypotenuse side of the angle ∠FGE.

So opposite side of ∠FGE is FE and hypotenuse side of ∠FGE is FG.

Substituting the values,

$\sin x=\dfrac{FE}{FG}$

Given that length of FE is 12 inch and FG is 18.6 inch.

Substituting the value,

$\sin x=\dfrac{12}{18.6}$

To find the value of x, taking inverse sin.

$x=\arcsin \left(\dfrac{12}{18.6}\right)$

Calculating the value,

$x=40.17$

Rounding to nearest tenth the value of angle is 40.2

Therefore measure of ∠FGE is 40.2° .

8 0

3 years ago

The scale on a map is 3 inches for every 6 1/4 miles. If the distance on the map is 5 1/2 inches, how far apart are the cities i

vovikov84 [41]

I think it is 34 3/8

4 0

3 years ago

Pls help me out and pls explain

LenKa [72]

Answer:

It is a function

Step-by-step explanation:

The x has only one y and that makes it a function

5 0

2 years ago

Which two tables represent the same function?

topjm [15]

Answer:

The 1st and the 5th tables represent the same function

Step-by-step explanation:

* Lets explain how to solve the problem

- There are five tables of functions, two of them are equal

- To find the two equal function lets find their equations

- The form of the equation of a line whose endpoints are (x1 , y1) and

(x2 , y2) is $\frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

* Lets make the equation of each table

# (x1 , y1) = (4 , 8) and (x2 , y2) = (6 , 7)

∵ x1 = 4 , x2 = 6 and y1 = 8 , y2 = 7

∴ $\frac{y-8}{x-4}=\frac{7-8}{6-4}$

∴ $\frac{y-8}{x-4}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 8) = -1(x - 4) ⇒ simplify

∴ 2y - 16 = -x + 4 ⇒ add x and 16 for two sides

∴ x + 2y = 20 ⇒ (1)

# (x1 , y1) = (4 , 5) and (x2 , y2) = (6 , 4)

∵ x1 = 4 , x2 = 6 and y1 = 5 , y2 = 4

∴ $\frac{y-5}{x-4}=\frac{4-5}{6-4}$

∴ $\frac{y-5}{x-4}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 5) = -1(x - 4) ⇒ simplify

∴ 2y - 10 = -x + 4 ⇒ add x and 10 for two sides

∴ x + 2y = 14 ⇒ (2)

# (x1 , y1) = (2 , 8) and (x2 , y2) = (8 , 5)

∵ x1 = 2 , x2 = 8 and y1 = 8 , y2 = 5

∴ $\frac{y-8}{x-2}=\frac{5-8}{8-2}$

∴ $\frac{y-8}{x-2}=\frac{-3}{6}=====\frac{y-8}{x-2}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 8) = -1(x - 2) ⇒ simplify

∴ 2y - 16 = -x + 2 ⇒ add x and 16 for two sides

∴ x + 2y = 18 ⇒ (3)

# (x1 , y1) = (2 , 10) and (x2 , y2) = (6 , 14)

∵ x1 = 2 , x2 = 6 and y1 = 10 , y2 = 14

∴ $\frac{y-10}{x-2}=\frac{14-10}{6-2}$

∴ $\frac{y-10}{x-2}=\frac{4}{4}======\frac{y-10}{x-2}=1$

- By using cross multiplication

∴ (y - 10) = (x - 2)

∴ y - 10 = x - 2 ⇒ add 2 and subtract y in the two sides

∴ -8 = x - y ⇒ switch the two sides

∴ x - y = -8 ⇒ (4)

# (x1 , y1) = (2 , 9) and (x2 , y2) = (8 , 6)

∵ x1 = 2 , x2 = 8 and y1 = 9 , y2 = 6

∴ $\frac{y-9}{x-2}=\frac{6-9}{8-2}$

∴ $\frac{y-9}{x-2}=\frac{-3}{6}======\frac{y-9}{x-2}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 9) = -1(x - 2) ⇒ simplify

∴ 2y - 18 = -x + 2 ⇒ add x and 18 for two sides

∴ x + 2y = 20 ⇒ (5)

- Equations (1) and (5) are the same

∴ The 1st and the 5th tables represent the same function

3 0

3 years ago