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3 years ago

Answer pleaseee 20 points ASAPPPP

Mathematics

1 answer:

shusha [124]3 years ago

6 0

Answer:

There isn't a question-

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Ben drinks tea at an incredible rate. He drinks 3 1/2 liters of tea every 2/3 of an hour. Ben drinks tea at a constant rate. How

s344n2d4d5 [400]

Divide 3 1/2 by 2/3. 3 1/2 = 7/2 as an improper fraction, so we have 7/2 ÷ 2/3 = 7/2 * 3/2 = 21/4 = 5 1/4 L

5 0

3 years ago

Read 2 more answers

Solution set for (6y+4)-(3+5y)=9

loris [4]

Y = 8 hoped it helped!

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4 years ago

After 8 hours of snow, the

Dmitrij [34]

Answer: -21.125 or -21 1/8 degrees

Explanation: Divide the number of degrees (-169) by the amount of time it was snowing (8) to get the answer (-21.125).

-169÷8=-21.125

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3 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

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4 years ago

NEED HELP IMMEDIATELY Which expression is equivalent to one over four n − 16?

Gemiola [76]

B. 1/4(n - 64)

Multiplying n and -64 by 1/4 leaves you with 1/4n - 16, the original equation.

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3 years ago