3 years ago

2x^2-x-6 Solve the quadratic equation

Mathematics

2 answers:

Pepsi [2]3 years ago

7 0

Factoring out this equation would be (2x+3)(x-2)

tatuchka [14]3 years ago

4 0

This is all i can get

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Which is the value of this expression when j = negative 2 and k = negative 1?

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Answer:

Option A.

Step-by-step explanation:

It is given that

$j=-2, k=-1$

The given expression is

$\left(\dfrac{jk^{-2}}{j^{-1}k^{-3}}\right)^3$

Substitute the given values in the above expression.

$\left(\dfrac{(-2)(-1)^{-2}}{(-2)^{-1}(-1)^{-3}}\right)^3$

$\Rightarrow \left(\dfrac{(-2)(1)}{\dfrac{1}{-2}(-1)}\right)^3$

$\Rightarrow \left(\dfrac{-2}{\dfrac{1}{2}}\right)^3$

$\Rightarrow \left(-4\right)^3$

$\Rightarrow -64$

Therefore, the correct option is A.

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They are both correct 8/4 simplified is 2. 1/4 times 8 equals 8/4 or 2

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