We are asked to solve for the angle of BDC in the figure which is rectangle ACBD.
Since it is a rectangle, each corner has a 90°. Initially, it was given that angle BDA is equal to 50°. Then we can solve for BDC, such as the solution is shown below:
90° = ∠ BDC + ∠ BDA
90° = ∠BDC + 50°
∠BDC = 90° - 50°
∠ BDC = 40°
The answer is 40°.
Answer:
13x for A, 7f for B
Step-by-step explanation:
8x+5x=13x (Because 8+5=13)
9f+10f=19f
Subtract 12f and you get 7f
We are asked to prove tan(θ / 2) = sin θ / (1 + cos θ). In this case, tan θ is equal to sin θ / cos θ. we can apply this to the equality. sin θ is equal to square root of (1-cos θ)/2 while cos θ is equal to <span>square root of (1 + cos θ)/2.
Hence, when we replace cos </span><span>θ with </span>square root of (1-cos θ)/2, we can prove already.
Answer:
x = 6
x = -1
x = 1
Step-by-step explanation:
Given:
Correct equation;
P(x) = x³ - 6x² - x + 6
Computation:
x³ - 6x² - x + 6
x²(x-6)-1(x-6)
(x-6)(x²-1)
we know that;
a²-b² = (a+b)(a-b)
So,
(x-6)(x²-1)
(x-6)(x+1)(x-1)
So,
zeroes are;
x = 6
x = -1
x = 1
Answer:
96
Step-by-step explanation:
6a²
Put a as 4.
6(4)²
Solve for power first.
6(16)
Multiply both terms.
= 96
