So hmm notice the picture below
I've included the "far arc - near arc" equation to get the angle made by both tangents
now, if we make k = x, which is your case
and we make the "near arc" to "x", which is also the case
and then we make the "far arc" to say "b"
so using the "far arc - near arc" equation, we get that
<h3>
Answer: B) 49.22</h3>
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Work Shown:
cos(angle) = adjacent/hypotenuse
cos(43) = 36/x
x*cos(43) = 36
x = 36/cos(43)
x = 49.2237885995494
x = 49.22
Your calculator needs to be in degree mode.
Answer:
8 x^5 y^7
Step-by-step explanation:
Simplify the following:
4×2 x^2 y^3 x^3 y^4
Hint: | Combine products of like terms.
4 x^2 y^3×2 x^3 y^4 = 4 x^(2 + 3) y^(3 + 4)×2:
4×2 x^(2 + 3) y^(3 + 4)
Hint: | Evaluate 3 + 4.
3 + 4 = 7:
4×2 x^(2 + 3) y^7
Hint: | Evaluate 2 + 3.
2 + 3 = 5:
4×2 x^5 y^7
Hint: | Multiply 4 and 2 together.
4×2 = 8:
Answer: 8 x^5 y^7
Answer:
<h2>The last costumers got 2.25 kilograms of chocolate candies.</h2>
Step-by-step explanation:
The question is
<em>
There is 11.73 kg of chocolate candies in the grocery store. The first customer bought 48 dag of candies. A second customer bought 4/5 of the remaining quantity. The last three customers bought the same amount of candy. How much chocolate did the last customers get?</em>
<em />
Givens
- The total amount of chocolate candies is 11.73 kilograms.
- First costumer bought 48 dag of candies. (1 kg equals 100 dags)
- Second costumer bougth 4/5 of the remaining.
- Another three costumers bought the same amount of candy.
Let's transform 48 dag to kilograms.
Therefore, the first costumer bought 0.48 kilograms of candies.
The remaining amount is: 
Now, we need to multiply the remaining amount of candies with 4/5
Therefore, the second costumer bought 9 kilograms of chocolate candies.
At last, we need to find the new remaining part of candies, which is
Therefore, the last costumers got 2.25 kilograms of chocolate candies.
We can use a variable equation to solve this. Let A represent alan's age, B represent bob's age, and C represent Cindy's age. So Bob's age would be Alan's age - 5, or a -5 = B. Then Bob's age would be double Cindy's age, so that means 2 multiplied by Cindy's age = Bob's age, or 2C = B. Your two equations are:
A - 5 = B
2C = B
Also a third equation that helps is A + B + C = 20.
Finally, here are the ages.
Alan = 11 years old
Bob = 6 years old
Cindy = 3 years old.
PS: Sorry, I'm not that good at explaining things, but here are the answers
