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tatiyna
3 years ago
15

Patti green and her husband are purchasing a condominium for $123,000. They have $15,000 for a down payment. What is the amount

of their mortgage loan?
Mathematics
1 answer:
Inessa [10]3 years ago
6 0

Answer:

The amount of their mortgage loan is $108000

Step-by-step explanation:

we are given

total purchasing amount =$123000

down payment amount = $15000

we know that

Mortgage loan amount =  (total purchasing amount)-(down payment amount)

now, we can plug value

Mortgage loan amount = $123000-$15000

Mortgage loan amount =$108000

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(a + b)(a 2 - ab + b 2)
JulsSmile [24]

Answer:

a³ + b³

Step-by-step explanation:

Given

(a + b)(a² - ab + b²)

Each term in the second factor is multiplied by each term in the first factor, that is

a(a² - ab + b²) + b(a² - ab + b²) ← distribute both parenthesis

= a³ - a²b + ab² + a²b - ab² + b³ ← collect like terms

= a³ + b³

4 0
3 years ago
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(06.06 MC) The work of a student to find the dimensions of a rectangle of area 8 + 12x and width 4 is shown below:
zheka24 [161]

Answer:

step 2

Step-by-step explanation:

theres a one in front of the () meaning it should have look like this

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2 years ago
Laquita practiced 60 math facts. Kinman practiced 15 more facts than Laquita. How many math facts did they practice in all?
Afina-wow [57]

Answer:

They practiced a total of 75 math facts in all!

60 + 15 = 75 :D

5 0
2 years ago
Yasmin sees a tent on sale for $243. The sale tag say the price is 20% off the original price. What was the original price A. $3
wel

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5 0
2 years ago
Help is appreciated! Thanks!
sukhopar [10]

Answer:

  1. 16√3
  2. -45+15i
  3. √255
  4. 6√2 +3√10

Step-by-step explanation:

1)

-4i\sqrt{-48}=-4i\sqrt{(-1)(4^2)(3)}=(-4i)(4i)\sqrt{3}=16\sqrt{3}

__

2)

(-5-5i)(3-6i)=-5(3-6i)-5i(3-6i)=-15+30i-15i+30i^2=-15-30+15i\\\\=-45+15i

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3)

\sqrt{3}\sqrt{5}\sqrt{17}=\sqrt{3\cdot 5\cdot 17}=\sqrt{255}

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4)

\sqrt{3}(\sqrt{24}+\sqrt{30})=\sqrt{3\cdot 24}+\sqrt{3\cdot 30}=\sqrt{6^2\cdot 2}+\sqrt{3^2\cdot 10}\\\\=6\sqrt{2}+3\sqrt{10}

_____

The applicable identities are ...

\sqrt{a^2b}=a\sqrt{b}\\\\i^2=-1

7 0
3 years ago
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