The question is incomplete, as the depth of the hook isn't given in the question. However, using a proposed depth for the hook, we could give a stepwise solution to the exercise.
Answer:
Kindly check explanation
Step-by-step explanation:
If given a hook depth of 6 meters, and a distance of 8 m(fishing line from hook) at the the Same depth, then the distance between rose and the fish, x can be calculated, using the relation.
Hypotenus² = opposite² + adjacent²
(refer to attached picture)
x² = 6² + 8²
x² = 36 +. 64
x² = 100
x = sqrt(100)
x = 10 meters
You can use the actual depth value to obtain the actual solution to your question.
Remember that in PEMDAS, you do the parentheses first.
1. For each answer choice, do whatever is in the parentheses first.
2. Multiply that number to the one outside the parentheses
Hint: For this problem, If all the signs in the answer choice are multiplication, they will equal the same number.
Answer:
z = 62
y = 117
Step-by-step explanation:
Z
118 and z are supplementary.
z + 118 = 180 Supplementary angles add to 180. Subtract 118 from both sides.
z = 180 - 118 Do the subtraction
z = 62 Answer
Y
The interior angles of all quadrilaterals (convex) add up to 360 degrees.
y + z + 84 + 97 = 360 Given
62 + y + 84 + 97=360 Add
y + 243 = 360 Subtract 243 from both sides
y = 360 - 243 combine
y = 117 Answer
84 ÷ 2 = 42
Check it to make sure.
2 × 42 = 84
42 and 2 can be multiplied to get 84.
1490 millimeters
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