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3 years ago

Please help me solve please show how you got the answer

Mathematics

1 answer:

zalisa [80]3 years ago

5 0

Answer:

Step-by-step explanation:

The total amount paid by a member according to this table is

Total Amount Paid = fee + monthly fee(# of months)

Since the fee is the same regardless of how many months one signs up for, it should come out the same for each row in our table.

Row 1:

TAP = fee + 15(#months)

135 = fee + 15(4) and

135 = fee + 60 so

fee = $75

Row 2:

165 = fee + 15(6) and

165 = fee + 90 so

fee = $75

Row 3:

255 = fee + 15(12) and

255 = fee + 180 so

fee = $75

Apparently, the fee is $75.

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Answer:

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Step-by-step explanation:

It has a graphing calculator and it super easy to plug in.

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3 years ago

Solve the compound inequality<br><br>4 < x - 5 < 12

uysha [10]

4 < x - 5 < 12

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3 years ago

Plz only answer if you know :(( i’m stuck

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Which property can be used to show that 4r+3s+2r=6r+3s? Explain your answer.

riadik2000 [5.3K]

Distributed property because this property allows u two put 4r+2r because this equation is also (4xr)+(2xr) since they have the same variable u can put them together 4+2 is 6 and then just multiply by r so it’s 6r. And let’s not forget about 3s it doesn’t have the same variable so you can do 6r+3s which is what u got and is the correct answer 6r+3s is simplified but it’s the same as 4r+3s+2r

4 0

4 years ago

eight cards are drawn from a standard deck of 52 cards. how many hands off with cards contain exactly three queens and three jac

d1i1m1o1n [39]

Answer:

15,136 hands off with cards contain exactly three queens and three jacks.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Standard deck:

4 queens and 4 jacks.

The other 52 - 8 = 44 cards are neither queens nor jacks.

Wow many hands off with cards contain exactly three queens and three jacks?

3 queens from a set of 4.

3 jacks from a set of 4.

2 other cards(not queens neither jacks) from the other 44. So

$C_{4,3}C_{4,3}C_{44,2} = \frac{4!}{1!3!} \times \frac{4!}{1!3!} \frac{44!}{2!42!} = 4*4*22*43 = 15136$

15,136 hands off with cards contain exactly three queens and three jacks.

4 0

3 years ago