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3 years ago

Which of the following are characteristics of the graph of the reciprocal parent function? check all that apply

Mathematics

1 answer:

e-lub [12.9K]3 years ago

5 0

<h3>3 answers: Choice A, Choice C, Choice D</h3>

Basically, everything but choice B

===========================================

Explanation:

Lets go through the answer choices to see which are true or false.

For each, we'll be considering the graph of y = 1/x as shown below.

A. True. We have two branches that are completely separate and never meet up, and those two branches are in quadrants Q1 and Q3. Both curves are always decreasing (going downhill as you move from left to right). This is because if x is positive, then so is y = 1/x. If x is negative, then so is y = 1/x. Any point (x,y) is either composed of two positive coordinates or two negative coordinates.
B. False. A parabola is one single curve and we have two separate curves here.
C. True. A hyperbola is composed of two curves as the graph of y = 1/x shows.
D. True. The graph shows y = 1/x does not go through the origin. This is because we cannot have x = 0 in y = 1/x, or otherwise we have a division by zero error. A similar situation happens with y = 0 as well.

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Just need someone to explain how<br><br> I simplified it to -2a+15b/ 4

nikitadnepr [17]

Answer:

Step-by-step explanation:

3(4a + 6b) = 3*4a + 3*6b = 12a + 18b

-2(7a + b) = -2*7a + (-2)*b = -14a - 2b

$\frac{5[3(4a+6b)-2(7a+b)-b]}{20}=\frac{5[12a+18b-14a-2b-b]}{20}\\\\ \frac{5[-2a+15b]}{20}=\frac{15b-2a}{4}$

x =1/4

6 0

3 years ago

Read 2 more answers

The car is moving with a speed v0 = 48 mi/hr up the 4-percent grade, and the driver applies the brakes at point A, causing all w

lutik1710 [3]

Answer:

s = 0.2203 miles

Step-by-step explanation:

Given:

- The initial speed vo = 48 mi/hr

- The mass of the car m

- The coefficient of kinetic friction uk = 0.61

- The slope of the road 4-percent grade

Find:

Determine the stopping distance sAB. Repeat your calculations for the case when the car is moving downhill from B to A.

Solution:

- Apply the energy principle with work done against friction:

K.E_1 + P.E_1 = Wf + P_E_2 + K.E_2

- The final velocity of car is zero, K.E_2 = 0

The initial potential energy is set as zero, P.E_1 = 0

K.E_1 = Wf + P_E_2

0.5*m*vo^2 = Ff*s + m*g*h

Where, Ff is the frictional force:

Ff = uk*N

Where, N is the normal contact force between car and road. By equilibrium equation we have:

m*g*cos(θ) - N = 0

N = m*g*cos(θ)

Hence,

Ff = uk*m*g*cos(θ)

- The vertical distance travelled h is:

h = s*sin(θ)

- The energy equation is:

0.5*m*vo^2 = uk*m*g*cos(θ)*s + m*g*s*sin(θ)

0.5*vo^2 = uk*g*cos(θ)*s + g*s*sin(θ)

s*(uk*g*cos(θ) + g*sin(θ) ) = 0.5*vo^2

s = [0.5*vo^2 / (uk*g*cos(θ) + g*sin(θ) ) ]

- The slope = 4 / 100,

s = [0.5*48^2 / (0.61*8052.97*cos(2.29) + 8052.97*sin(2.29) ) ]

s = 0.2203 miles

3 0

4 years ago

An oil company fills 1/12 of a tank in 1/3 hour. At this rate, which expression can be used to determine how long it will take f

White raven [17]

Answer:

It's C

Step-by-step explanation:

Correct me if i'm wrong.

But it seems to make sense with my calculations....

6 0

3 years ago

Pls help with this one I give brainliest thank you! Number 7

Leona [35]

Answer:

length x width x height = volume

5.5 x 2 = 11 x 3 = 33

33 ft.

hope this helps

if you have any questions you can ask!

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

How are the solutions to the inequality -2x ≥ 10 different from the solutions to -2x > 10?

CaHeK987 [17]

Answer:

First lets find the solutions to each inequality.

-2x $\geq \\$ 10 and -2x>10 (divide both sides by -2 to solve)

x $\leq$ -5 and x<-5

x $\leq$ -5 tell us that x could be -5 or less.

x<-5 tells us that x could be -6 or less.

The first one is less than or equal to which tells you that there is a possibility that the number is shows is could be an answer

Hope this helps ;)

4 0

4 years ago