Use the distributive property to write two expressions that are equivalent to 12 +30x. Describe the steps you followed

Mathematics

1 answer:

Rufina [12.5K]3 years ago

7 0

You are supposed to factor a number out of both terms

2(6+15x)

You might be interested in

Two real solutions of tx^2+3x_7=0

Olegator [25]

The number of solutions of a quadratic equation

ax^2+bx+c=0

Depends on its discriminant

/Delta=b^2-4ac

If /Delta>0 there are two distinct solutions

If /Delta=0 there are two coincident solutions

If /Delta<0 there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

The number of solutions of a quadratic equation

Depends on its discriminant

If there are two distinct solutions

If there are two coincident solutions

If there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]

3 0

3 years ago

The diagram shows the diameter of a circular stump. Which of the following is the closest to the circumference of the stump? ♡

galina1969 [7]

Answer:

im doing it rn but i think its 10.99

Step-by-step explanation:

6 0

2 years ago

If u(x)=-2x²+3 and v(x)=1/x, what is the range of (u ° v)(x)?

Ludmilka [50]

$u(x)=-2x^2+3\\\\v(x)=\dfrac{1}{x}\\\\(u\ \circ\ v)(x)=-2\left(\dfrac{1}{x}\right)^2+3=-2\left(\dfrac{1}{x^2}\right)+3=-\dfrac{1}{x^2}+3\\\\\text{The range of}\ y=\dfrac{1}{x^2}\ \text{is all positive real numbers.}\\\\\text{The range of}\ y=-\dfrac{1}{x^2}\ \text{is all negative real numbers.}\\\\\text{The range of }\ (u\ \circ\ v)(x)=-\dfrac{1}{x^2}+3\ is\ (-\infty,\ 3)$