Answer: Should be 150mm
Step-by-step explanation:
Find the surface area of each figure. Round answers to the nearest tenth, if necessary
2 mm-
2/5 mm
10 mm
3 mm
O
75 mm2
150 mm2
92 mm2
86 mm2
Answer:
f(x) = 4.35 +3.95·sin(πx/12)
Step-by-step explanation:
For problems of this sort, a sine function is used that is of the form ...
f(x) = A + Bsin(2πx/P)
where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.
It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...
f(x) = 4.35 + 3.95·sin(2πx/24)
The argument of the sine function can be simplified to πx/12, as in the Answer, above.
Answer:
5.5193237 times 10 to the power of -10
Step-by-step explanation:
To solve you just need to divided the area by the length or width the question has provided. Please note I am in 7th grade.
Diagonals are = n - 2
Interior = 144
Exterior angle = 180 - 144 = 36
Formula for exterior of a regular polygon given the number of sides:
= 360/n
36 = 360/n
n = 360/36 = 10
n = 10
Number of diagonals = n - 2 = 10 - 2 = 8
8 diagonals.
7= 16 lb >16 Oz 16x16=256
8= 1500 lb < 2T 2000+2000
9= 3T>5999 lb 2000x3
10= 1600 Oz > 10 lb 1600÷16=100
11= 19 lb>300 Oz 19x16=304oz
12= 8 oz= 1/2 lb 16 ounces = 1 pound 1/2=8
13= pounds=6000 tons= 1, 1.5