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2 years ago

According to the box-and-whisker plot shown above, what are the following:

Mathematics

1 answer:

Readme [11.4K]2 years ago

4 0

Answer:

6. 80

7. 60

8. 100

9. 40

10. 110

Step-by-step explanation:

A box and whisker plot is a visual representation of the 5-number summary of a data set. The features of the plot are, left-to-right, the minimum, first quartile, median, third quartile, maximum.

You are being asked to identify the numerical value associated with each of these features.

The left whisker extends to the minimum of 40.

The left end of the box identifies the first quartile as 60.

The line in the middle of the box is the median, 80.

The right end of the box identifies the third quartile as 100.

The right whisker extends to the maximum of 110.

<em>Additional comment</em>

We hope you can rearrange the order of these numbers to suit the order in which the questions ask for them.

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UkoKoshka [18]

Answer:

-8n + 9

Step-by-step explanation:

Given that,

A = -3n + 2

B = 5n - 7

Before solving you have to know that,

( + ) × ( + ) = ( + )

( - ) × ( - ) = ( + )

( + ) × ( - ) = ( - )

Let us solve now.

A - B

-3n + 2 -(5n - 7)

-3n + 2 - 5n + 7

Combine like terms

-3n - 5n + 2 + 7

-8n + 9

Hope this helps you.

Let me know if you have any other questions :-)

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2 years ago

Which list of ordered pairs does NOT represent a function? A.(8, 80), (6, 80), (3, 80), (7, 80), (5, 80) B. (7, 80), (6, 60), (5

olga_2 [115]

Answer:

Step-by-step explanation:

Because they want you to see the number who is repeating like 80 in the later A is 4 times repeated. I hope it help

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2 years ago

Jim spins a spinner with colors red, blue, yellow, purple, green, and orange. Jim also flips a coin. What is the probability tha

S_A_V [24]

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In this case:

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3 years ago

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Let O be an angle in quadrant III such that cos 0 = -2/5 Find the exact values of csco and tan 0.

vivado [14]

well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

$cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}$

$\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}$

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2 years ago

Which quadratic equation is equivalent to (x^2-1)^2-11(x^2-1)+24=0

Y_Kistochka [10]

Answer:

The correct answer is first option

u² - 11u + 24 = 0

When u = (x² - 1)

Step-by-step explanation:

It is given that,

(x² - 1)² - (x² - 1) + 24 = 0

<u>To find the correct answer</u>

Substitute u = x² - 1

The equation becomes,

u² - 11u + 24 = 0 Where u = (x² - 1)

Therefore the correct answer is first option

u² - 11u + 24 = 0

When u = (x² - 1)

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3 years ago

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