Ask question

Ask question

All categories

3 years ago

6

Solve for x. Please help !

1 answer:

Ne4ueva [31]3 years ago

7 0

Answer:

x = 37 1/2
x = 2

Step-by-step explanation:

Parallel lines divide transversals proportionally. I like to write the proportions so the variable is in the numerator. Then the solution is obtained by multiplying by the denominator of the variable term.

1. x/20 = (46 -16)/16

x = 20(30/16)

x = 37.5

__

2. (x +4)/13.5 = 4/9

x +4 = 13.5(4/9) = 6

x = 6 -4

x = 2

You might be interested in

672,591 rounded to the nearest hundred thousand

chubhunter [2.5K]

672,591 is your current number. So find the number in the hundred-thousand place, which is 6. Now go to the number that is on its right. So next to the 6 is 7. That means it goes up. So your answer would be about 700,000.

7 0

4 years ago

A water desalination plant can produce 2x10^6 gallons of water in one day. How many gallons can it produce in 8.7 days?

arlik [135]

Answer:

2x10^6 = 2 Million gallons of water.

8.7 days = 209 hours

209 x 2,000,000/24 = 17,416,666.6667 Gallons of Water in 8.7 days

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Is (5,0) , (4,2), (3,4), (2,6), (1,8) a linear function?

Wittaler [7]

Answer:

Yes

Step-by-step explanation:

Is (5,0) , (4,2), (3,4), (2,6), (1,8) a linear function?

Yes, it is a linear function.

4 0

3 years ago

Determine which of the following sets of three points constitute the vertices of a right triangle: (a) 3 + 5i,2 +2i,5i; (b)2i,3

Illusion [34]

Answer:

Option (c) is correct

Step-by-step explanation:

Case (a)

A = 3 + 5i = (3, 5)

B = 2 + 2i = (2, 2)

C = 5i = (0, 5)

Use the distance formula to find the distance between two points

$AB = \sqrt{(2-3)^{2}+(2-5)^{2}}=\sqrt{10}$

$BC = \sqrt{(0-2)^{2}+(5-2)^{2}}=\sqrt{13}$

$CA = \sqrt{(0-3)^{2}+(5-5)^{2}}=\sqrt{9}$

For the triangle to be right angles triangle

$BC^{2}=AB^{2}+CA^{2}$

Here, it is not valid, so these are not the points of a right angled triangle.

Case (b)

A = 2i = (0, 2)

B = 3 + 5i = (3, 5)

C = 4 + i = (4, 1)

Use the distance formula to find the distance between two points

$AB = \sqrt{(3-0)^{2}+(5-2)^{2}}=\sqrt{18}$

$BC = \sqrt{(4-3)^{2}+(1-5)^{2}}=\sqrt{17}$

$CA = \sqrt{(4-0)^{2}+(1-2)^{2}}=\sqrt{17}$

For the triangle to be right angles triangle

$AB^{2}=BC^{2}+CA^{2}$

Here, it is not valid, so these are not the points of a right angled triangle.

Case (c)

A = 6 + 4i = (6, 4)

B = 7 + 5i = (7, 5)

C = 8 + 4i = (8, 4)

Use the distance formula to find the distance between two points

$AB = \sqrt{(7-6)^{2}+(5-4)^{2}}=\sqrt{2}$

$BC = \sqrt{(8-7)^{2}+(4-5)^{2}}=\sqrt{2}$

$CA = \sqrt{(8-6)^{2}+(4-4)^{2}}=\sqrt{4}$

For the triangle to be right angles triangle

$CA^{2}=BC^{2}+AB^{2}$

Here, it is valid, so these are the points of a right angled triangle.

7 0

3 years ago

The radius of a circular musical drum is 70 centimeters.<br> Find its area.<br> Use 7 = - 3.14

Kazeer [188]

Answer:

I got 219.8 as my answer, hope this helps!

7 0

3 years ago