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klemol [59]
3 years ago
6

Select all the expressions that all have the following quotient 2m+3

Mathematics
1 answer:
Leno4ka [110]3 years ago
6 0

Answer:

1, 2 and 4

Step-by-step explanation:

1.32m2/16m +48m/16m =2m +3

2.4m2/2m +6m/2m =2m+3

4.10m2 /5m +15m/5m= 2m+3

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Answer: i am pretty sure the answer is either A or C

Step-by-step explanation:

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sweet-ann [11.9K]

Answer:

A = 33 1/3 ft²

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Step-by-step explanation:

3 0
3 years ago
What is the value of K?
Ksju [112]
Answer: The value of k for which one root of the quadratic equation kx2 - 14x + 8 = 0 is six times the other is k = 3.
Let's look into the solution step by step.

Explanation:

Given: A quadratic equation, kx2 - 14x + 8 = 0

Let the two zeros of the equation be α and β.

According to the given question, if one of the roots is α the other root will be 6α.

Thus, β = 6α

Hence, the two zeros are α and 6α.

We know that for a given quadratic equation ax2 + bx + c = 0

The sum of the zeros is expressed as,

α + β = - b / a

The product of the zeros is expressed as,

αβ = c / a

For the given quadratic equation kx2 - 14x + 8 = 0,

a = k, b = -14, c = 8

The sum of the zeros is:

α + 6α = 14 / k [Since the two zeros are α and 6α]

⇒ 7α = 14 / k

⇒ α = 2 / k --------------- (1)

The product of the zeros is:

⇒ α × 6α = 8 / k [Since the two zeros are α and 6α]

⇒ 6α 2 = 8 / k

⇒ 6 (2 / k)2 = 8 / k [From (1)]

⇒ 6 × (4 / k) = 8

⇒ k = 24 / 8

⇒ k = 3
6 0
3 years ago
Which expressions are completely factored? Select each correct answer. 32y10−24=8(4y10−3) 18y3−6y=3y(6y2−2) 16y5+12y3=4y3(4y2+3)
laila [671]

Answer:

Option A and Option C

Step-by-step explanation:

Option A: 32y^{10}-24 = 8(4y^{10}-3) This is completely factored as 8 is the Highest Common Monomial factor

Option B: 18y^{3}-6y = 3y(6y^{2}-2) This is not completely factored as 2 is still a common factor of 6y2 and -2.

Option C: 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) This is completely factored as 4y2 is the Highest Common Monomial factor

Option D: 20y^{7}+10y^{2} = 5y(4y^{6}+2y) This is not completely factored as 2y is still a common factor of 4y6 and 2y.

So the options that are completely factored are Option A and Option C

3 0
3 years ago
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