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Lorico [155]
3 years ago
8

Given: 3x - 2 ≤ 2x + 1.

Mathematics
1 answer:
Natasha2012 [34]3 years ago
5 0

Answer:

\boxed{\boxed{\pink{\bf \leadsto Hence \ the\  correct \ option \ is \ 2 . }}}

Step-by-step explanation:

A inequality is given to us and we need to find the solution set . The inequality given to us is :-

\bf \implies 3x -2 \geq 2x + 1 \\\\\bf\implies 3x - 2x \geq 2 + 1 \\\\\bf\implies\boxed{\bf x \geq 3}

This means that x belongs to Real Numbers. Hence final answer would be :-

\boxed{\red{\bf { x | x \in R , x \geq 3 }}

<h3><u>Hence</u><u> </u><u>option</u><u> </u><u>2</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u></h3>

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A particular computer takes 11 minutes to download a 44 minute TV show. How long will it take the computer to download a 1.5 hou
motikmotik
44/11= 4
4 minutes of the movie are downloaded each minute.
1.5 hours= 90 min
90/4= 22.5 minutes
3 0
3 years ago
Read 2 more answers
A phone manufacturer wants to compete in the touch screen phone market. Management understands that the leading product has a le
CaHeK987 [17]

Answer:

Step-by-step explanation:

Hello!

To compete in the touch screen phone market a manufacturer aims to release a new touch screen with a battery life said to last more than two hours longer than the leading product which is the desired feature in phones.

To test this claim two samples were taken:

Sample 1

X: battery lifespan of a unit of the new product (min)

n= 93 units of the new product

mean battery life X[bar]= 8:53hs= 533min

S= 84 min

Sample 2

X: battery lifespan of a unit of the leading product (min)

n= 102 units of the leading product

mean battery life X[bar]= 5:40 hs = 340min

S= 93 min

The population variances of both variances are unknown and distinct.

To test if the average battery life of the new product is greater than the average battery life of the leading product by 2 hs (or 120 min) the parameters of interest will be the two population means and we will test their difference, the hypotheses are:

H₀: μ₁ - μ₂ ≤ 120

H₁:  μ₁ - μ₂ > 120

Considering that there is not enough information about the distribution of both variables, but both samples are big enough, we can apply the central limit theorem and approximate the distribution of both sample means to normal, this way we can use the standard normal:

Z= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{\sqrt{\frac{S_1^2}{n_1} +\frac{S_2^2}{n_2}  } }

Z≈N(0;1)

Z= \frac{(533-340)-120}{\sqrt{\frac{84^2}{56} +\frac{93^2}{102}  } }= 5.028

I hope this helps!

3 0
4 years ago
Is it true w is the set of (s,w,n,t,c)
umka21 [38]

Answer:

{w} is the SUBSET of   {s,w,n,t,c}

Step-by-step explanation:

SUBSET: Any set  P is called a SUBSET of a set Q is ALL ELEMENTS of P are in the set Q.

i.e P ⊂ Q

Here, the given set  Q  =  {s,w,n,t,c}

Also, set P = {w}

Now,as the element w of set P is also an element of set Q.

⇒ P is the SUBSET of  Q

⇒ P ⊂ Q

⇒  {w} ⊂  {s,w,n,t,c}

Hence,   {w} is the SUBSET of   {s,w,n,t,c}.

5 0
4 years ago
You have a coupon for a restaurant. You save $3 on a meal. What was the original cost of the meal?
Zanzabum
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6 0
3 years ago
How many solutions does -(9x+12)=-8x-(x+3) have
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-(9x+12)=-8x-(x+3)
-9x-12= -8x-x-3
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-9

if u look at the eq for x it has no value. but if u r asking a solution for a eq then it is -9
4 0
3 years ago
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