<h3>☂︎ Answer :- </h3>
<h3>☂︎ Solution :- </h3>
- LCM of 5 , 18 , 25 and 27 = 2 × 3³ × 5²
- 2 and 3 have odd powers . To get a perfect square, we need to make the powers of 2 and 3 even . The powers of 5 is already even .
In other words , the LCM of 5 , 18 , 25 and 27 can be made a perfect square if it is multiplied by 2 × 3 .
The least perfect square greater that the LCM ,
☞︎︎︎ 2 × 3³ × 5² × 2 × 3
☞︎︎︎ 2² × 3⁴ × 5²
☞︎︎︎ 4 × 81 × 85
☞︎︎︎ 100 × 81
☞︎︎︎ 8100
8100 is the least perfect square which is exactly divisible by each of the numbers 5 , 18 , 25 , 27 .
To answer problems like this you have to use binomial:
P (x > 1) = 1 – p (0
< x < 1) > .7
So:
1 – p (0) – p (1) >
.7
1 – (3/ 4) ^n – (3/ 4)
^n (n – 1 ) (1/ 4) > .7
Therefore n > 5.185,
and the smallest value of n so that we can satisfy the given condition is 6
(rounded up)
<span> </span>
Answer:
-2r^3+4r^2+12r-4
Step-by-step explanation:
6r^3-2r^2+12r-4-8r^3+6r^2
(6r^3-8r^3)+(-2r^2+6r^2)+12r-4
simplify
-2r^3+4r^3+12r-4
Most graphing calculators will do weighted averages pretty easily. It is mostly a matter of data entry.
mx = -2
my = 10
(x, y) = (mx, my)/10 = (-0.2, 1)
