suppose that y and z are points on a number line if y z equals 16 + y lies at -4 where could z be located
1 answer:
<u>Corrected Question</u>
Suppose that y and z are points on a number line if yz equals 16 and y lies at -4. Where could z be located?
Answer:
z would be located at -4.
Step-by-step explanation:
If the product of y and z, yz=16
Point y lies at -4.
Substituting y=-4 into yz=16, we obtain:
Divide both sides by -4
Therefore, <u>z would be located at -4</u>, which is the same point at which y is located.
y and z are the same points on the number line.
We know our result is correct because the product of two negative numbers is positive.
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Answer:
<h2>Function 1 has the least minimum value and its coordinates are (2. - 7).</h2>Step-by-step explanation:
The first function is
The second function is
x g(x)
-2 2
-1 -3
0 2
1 17
The vertex has coordinates of , where
and
.
Let's find the vertex for the first function where and
.
Therefore, the vertex of the first function is at .
Now, the minimum value of the second function can be deducted from its table, which is .
Therefore, has -7 as minimum value and
has -3 as minimum vale.
So, the right answer is B, because -7 is less than -3.