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laiz [17]
2 years ago
10

The graph shows the vertical displacement y, in centimeters, that a weight bouncing from a

Mathematics
1 answer:
Lana71 [14]2 years ago
8 0

The weights maximum displacement is just the amplitude of the graph. The highest or lowest point it reaches. So C 16cm.

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Simplify 2a+2−3a−5+a−4+7a.
zhuklara [117]

Answer:

7a-7

Step-by-step explanation:

2a+2−3a−5+a−4+7a.

Combine like terms

2a-3a+a+7a+2-5-4

7a-7

3 0
2 years ago
Read 2 more answers
14 (OM) Radicals and Estimation (2 pts) Without a calculator, estimate the radical and explain how you estimated. Then using a c
Irina-Kira [14]

Q) Without a calculator, we must estimate the value of the following expression:

3-\sqrt[]{38}.

A) I estimate 3 - √38 to be approximately -3.2.

First, we estimate the value of √38. √38 is between √36 and √49, but close to √36 (since 38 is closer to 4 than it is to 9). Since √36 is 6, √38 is probably something like 6.1 or 6.2. Filling 6.2 in the expression and simplifying, we have this:

3-6.2=-3.2.

So, I expect the number 3 - √38 to be close to -3.2.

Using a calculator we find that: 3 - √38 ≅ -3.16, which it is approximately the result that we found.

Answer

Without a calculator we find that 3 - √38 ≅ -3.2.

5 0
1 year ago
A survey claims that a college graduate from Smith College can expect an average starting salary of $ 42,000. Fifteen Smith Coll
jek_recluse [69]
<h2>Answer with explanation:</h2>

Let \mu be the average starting salary ( in dollars).

As per given , we have

H_0: \mu=42000\\\\ H_a:\mu

Since H_a is left-tailed , so our test is a left-tailed test.

WE assume that the starting salary follows normal distribution .

Since population standard deviation is unknown and sample size is small so we use t-test.

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}} , where n= sample size , \overline{x} = sample mean , s = sample standard deviation.

Here , n= 15 , \overline{x}=  40,800  , s= 225

Then, t=\dfrac{40800-42000}{\dfrac{2250}{\sqrt{15}}}\approx-2.07

Degree of freedom = n-1=14

The critical t-value for significance level α  = 0.01 and degree of freedom 14 is 2.62.

Decision : Since the absolute calculated t-value (2.07) is less than the  critical t-value., so we cannot reject the null hypothesis.

Conclusion : We do not have sufficient evidence at 1 % level of significance to support the claim that  the average starting salary of the graduates is significantly less that $42,000.

3 0
2 years ago
Determine the degree of the relation y = 8x^4 – 3x^3 + x^2.<br><br> a) 4<br> b) 3<br> c) 1<br> d) 2
BlackZzzverrR [31]

Answer:

x= 2x+3

Step-by-step explanation:

delta= postif

x1= -b - racine de Delta sur A AU CARRE

x2= -b + racine de delta A AU CARRE

8 0
2 years ago
Find the number of ways in which a student can choose 5cource out of 9 course?<br>​
Kaylis [27]

Answer:

please mark as brainliest

7 0
3 years ago
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