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tensa zangetsu [6.8K]
3 years ago
15

Offspring that result from sexual reproduction each have

Biology
1 answer:
Nostrana [21]3 years ago
4 0

Answer: a haploid chromosome set from each parent

Explanation:

I infer this from the question which was “Offspring that result from sexual reproduction each have”

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What type of graph is a and b please help me​
vredina [299]

you could chose to describe the first graph as any of the following phrases:

‘curved graph’

‘intercept on y-axis’

‘as x increases, y increases’,

‘y increases slowly at first, then more rapidly, then slows down again’ and ‘reaches a maximum level’.

you can chose to describe the second graph as any of the following phrases:

'gradually increases, then rapidly increases in a short period of time"

3 0
2 years ago
What is the main function of xylem tissue in the plant transport system?
mario62 [17]
The main function of xylem tissue in the plant transport system is to transport water.

Answer: C) or the third option.
8 0
3 years ago
Which of the following would be the easiest way to diagram predatory and parasitic relationships between several species?
kumpel [21]

Answer:

C.

Explanation:

Food chains focus on one set of organisms and their predators/prey, while food webs show multiple for each. Hope this helps. :)

8 0
3 years ago
Various colors of light are tested to see which growth promotes the best
laila [671]
You need more context to the question, however I think I have it figured out.
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3 0
3 years ago
Small body (nb), short spines (Is) and amoral are three recessive traits in stick the genes of which are linked on the same chro
melomori [17]

Answer:

The three genes in coupling are in repulsion.

Explanation:

Coupling happens when the dominant alleles and the recessive alleles are on the same homologous chromosome, while the repulsion happens when one chromosome has one dominant allele and one recessive allele and another homologous chromosome also has dominant and recessive alleles.

If the progeny has:

nb+ ls+ a/nb ls a ⇒ nb+ ls+ a

nb ls a+/nb ls a ⇒ nb ls a+

Where nb+ ls+ a is the dominant alleles and nb and nb+ is in middle.

ls+ nb+ are on the same chromosome (both dominant)

ls nb are on the same chromosome (both recessive)

ls nb, these two are in coupling with each other, but ls+ and a are on the chromosome and ls+ or nb+ are dominant, while nb+ and a are recessive on form a, thus, ls and nb, they are in repulsion with a.

3 0
2 years ago
Read 2 more answers
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