The disk method will only involve a single integral. I've attached a sketch of the bounded region (in red) and one such disk made by revolving it around the y-axis.
Such a disk has radius x = 1/y and height/thickness ∆y, so that the volume of one such disk is
π (radius) (height) = π (1/y)² ∆y = π/y² ∆y
and the volume of a stack of n such disks is

where
is a point sampled from the interval [1, 5].
As we refine the solid by adding increasingly more, increasingly thinner disks, so that ∆y converges to 0, the sum converges to a definite integral that gives the exact volume V,


Answer:
x ≤ 3
Step-by-step explanation:
Given
2(4 + 2x) ≥ 5x + 5 ← distribute parenthesis on left side
8 + 4x ≥ 5x + 5 ( subtract 4x from both sides )
8 ≥ x + 5 ( subtract 5 from both sides )
3 ≥ x , hence
x ≤ 3
Answer:
Obtuse, isosceles
Step-by-step explanation:
Classify. Two same length sides make it isosceles
A larger angle than 90° make it obtuse
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Answer:
3.1
Step-by-step explanation:
Since this is area and you are given the width must divide area by width ( A/W = L) 13.02 divided by 4.2 = 3.1. You can check this by doing 3.1 multiplied by 4.2. It should give you 13.02
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