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VladimirAG [237]
3 years ago
10

Emily would like to buy some new

Mathematics
1 answer:
bonufazy [111]3 years ago
6 0

Answer:

$14,277.80

Step-by-step explanation:

The standard formula for compound interest is given as;

A = P(1+r/n)^(nt) .....1

Where;

A = final amount/value

P = initial amount/value (principal)

r = rate yearly

n = number of times compounded yearly.

t = time of investment in years

For this case;

P = $7,400

t = 8 years

n = 4 (quarterly)

r = 9.5% = 0.095

Using equation 1.

A = $7,400(1+0.095/4)^(4×7)

A = $7,400(1.02375)^(28)

A = $7,400(1.929432606035)

A = $14,277.80

final amount/value after 8 years A =$14,277.80

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faltersainse [42]

Answer:

91

Step-by-step explanation:

shaded area= area of rec - area of semi circle

A= 12*14- 1/2*22/7*7²= 91 cm²

note π=22/7 not 2/7

3 0
4 years ago
National Textile installed a new textile machine in one of its factories at a cost of $250,000. The machine is depreciated linea
kirill115 [55]

Answer:

The required expression is y=250,000-24,000 t

Step-by-step explanation:

Consider the provided information.

National Textile installed a new textile machine in one of its factories at a cost of $250,000.

That means for 0 year the cost of the machine is $250,000.

This can be written as: (0, 250,000)

Over 10 years with a scrap value of $10,000

That means for 10 year the cost of the machine is $10,000.

This can be written as: (10, 10,000)

Now first find the rate of change:

Rate of change=m=\frac{Rise}{Run}=\frac{10,000-250,000}{10-0}

Rate of change=m=\frac{Rise}{Run}=\frac{-240,000}{10}

Rate of change=m=\frac{Rise}{Run}=-24,000

Now use the point-slope form of an equation of a line with the point (0, 250,000), we can find the required expression.

(y-250,000)=-24,000(t-0)

y-250,000=-24,000 t

y=250,000-24,000 t

Hence, the required expression is y=250,000-24,000 t

6 0
3 years ago
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
frozen [14]

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

(x,y)\to (y,-x)

Using this rule, we get

A(-3,6)\to A'(6,3)

B(2,9)\to B'(9,-2)

C(1,1)\to C'(1,-1)

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).

7 0
4 years ago
Which choice shows the coordinates of C' if the trapezoid is reflected across the y-axis?
vivado [14]

Answer:

(-5, 3)

Step-by-step explanation:

5 0
3 years ago
Graph the equation x minus y divided by two equals x plus y divided by four
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I think this is it x-y÷2=x+y÷4
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