Let
x--------> the number of months
y-------> represents the balance, in dollars, of a bank account
we know that
y=-50x+100
the rate of change is equal to the slope of the line
so

therefore
<u>the answer is</u>
the rate of change is 
Answer:
p-q= -4
p=q-4
x^2 + px + q=0
=> x^2 + (q-4)x + q = 0
d= b^2-4ac
=(q-4)^2 - 4(1)(q)
= q^2 + 16 -8q - 4q
=q^2 -12q+16
given that D=16
q^2 -12q+16 = 16
=> q^2 -12q = 0
=> q^2 = 12q
=> q = 12q/q
=> q= 12
Therefore the value of q is 12 and the value of p is q-4 = 12-4= 8
Hope you understood............
Given:
Endpoints of segment AB are A(- 18, 5) and B(- 4, 5).
Point Z is located exactly 1/8 of the distance from A to B.
To find:
The value of the x-coordinate of point Z.
Solution:
Point Z is located exactly 1/8 of the distance from A to B.
AZ:AB=1:8
AZ:ZB = AZ:(AB-AZ)= 1:(8-1) = 1:7
It means point Z divided segment AB in 1:7.
Using section formula, the x coordinate of point Z is





Therefore, the required x-coordinate of point Z is -16.25.
Make a ratio, then cross multiply.
4/30=x/48
30x=4x48
30x=192
x=6.4