Answer: -6
Step-by-step explanation: It changed -6 each round because -6x3=-18.\
Hope this helped!
(2^6)=1
take log on both sides,
xlog(2^6)=log(1)=0
=>
x=0, since log(2^6)>0
5^0=1
there is no value of x appearing in the equation, so x can be any valid number.
Answer:
2(2q+7)(3q-2)=0
Step-by-step explanation:
lets set up the equation equal to 0:
12q^2+34q-28=0
now, lets factor:
2(6q^2+17q-14)=0
2(2q+7)(3q-2)=0
now, lets find the solutions:
2q+7=0
2q=-7
q=-3.5
3q-2=0
3q=2
q=2/3
Answer:
abc to rqp is the right ans
