Question

What is the slope of the line that passes through (4,-9) and (1,3)?

Answer 1

Answer:

$m=-4$; the slope is -4

Step-by-step explanation:

$slope=\frac{rise}{run} =\frac{y^2-y^1}{x^2-x^1}$

coordinates: (4,-9) (1,3)

$\frac{3-(-9)}{1-4}=\frac{-12}{-3} =-4$

= -4 is your answer

hope this helped

~rere

Answer 2

Answer:

slope = - 4

Step-by-step explanation:

calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (4, - 9 ) and (x₂, y₂ ) = 1, 3 )

m = $\frac{3-(-9)}{1-4}$ = $\frac{3+9}{-3}$ = $\frac{12}{-3}$ = - 4