3 years ago

Find the center of the circle with the equation x2 + y2 – 6x – 4y+12 = 0.With solution.

1 answer:

5 0

#x^2 - 6x +y^2 - 4y = 12

Then take 1/2 of the 'b' term for both quadratic expressions, square those values and add them to both sides.
#x^2 -6x + 9 + y^2 - 4y + 4 = 12 + 9 + 4
(x - 3)^2 + (y -2)^2 = 25

Circle centered at (3,2) with radius = 5

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Find the center of the circle with the equation x2 + y2 – 6x – 4y+12 = 0.With solution.​

Find the center of the circle with the equation x2 + y2 – 6x – 4y+12 = 0.With solution.