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3 years ago

Find the center of the circle with the equation x2 + y2 – 6x – 4y+12 = 0.With solution.

1 answer:

5 0

#x^2 - 6x +y^2 - 4y = 12

Then take 1/2 of the 'b' term for both quadratic expressions, square those values and add them to both sides.
#x^2 -6x + 9 + y^2 - 4y + 4 = 12 + 9 + 4
(x - 3)^2 + (y -2)^2 = 25

Circle centered at (3,2) with radius = 5

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Find the slope of the line that passes through (4, 6) and (1, 10).

Jlenok [28]

Answer:

given us,

(x1y1) = (4,6)

(x2y2)= (1,10)

here

slope= (y2-y1)/ (x2-x1)

= (10-6)/ (1-4)

= 4/ (-3)

Step-by-step explanation:

4/ (-3)

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3 years ago

Given the equation y = 4 + 2x find the values for y given the value x

Leviafan [203]

Answer:

If x = 3 then y = 10

If x = -3 then y = -2

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3 years ago

Given the function f(x) = 2|x + 6| – 4, for what values of x is f(x) = 6?

lara [203]

Answer:

x = -1 , - 11,

Step-by-step explanation:

| x | = x

|- x | = x

f(x) = 2 | x + 6 | - 4

x = - 1 , f( - 1) = 2 | - 1 + 6 | - 4 = 2 | 5 | - 4 = 10 - 4 = 6 , True

x = 1 , f( 1 ) = 2 | 1 + 6 | - 4 = 2 | 7 | - 4 = 14 - 4 = 10 , False

x = 11, f( 11 ) = 2 | 11 + 6 | - 4 = 2 | 17 | - 4 = 34 - 4 = 30 , False

x = - 11, f( - 11) = 2 | -11 + 6 | - 4 = 2 | - 5 | - 4 = 10 - 4 = 6 , True

x = 14 , f( 14 ) = 2 | 14 + 6 | - 4 = 2 | 20 | - 4 = 40 - 4 = 36 , False

x = -14 , f( - 14 ) = 2 | - 14 + 6 | - 4 = 2 | - 8 | - 4 = 16 - 4 = 12 , False

x = - 26 , f( - 26) = 2 | -26 + 6 | - 4 = 2 | -20 | - 4 = 40 - 4 = 36 , False

x = 26, f( 26 ) = 2 | 26 + 6 | - 4 = 2 | 32 | - 4 = 64 - 4 = 60 , False

Given f ( x ) = 6

f( x ) = 2 | x + 6 | - 4

6 = 2 | x + 6 | - 4

6 + 4 = 2 | x + 6| - 4 + 4 [ adding 4 to both sides ]

10 = 2 | x + 6 | + 0

5 = | x + 6 | [ dividing both sides by 2 ]

$- 5 =\ ( x+ 6) \ = 5\\\\$ $[ \ | x | = a\ => \ -a \ = x \ = a \ ]$

$- 5 - 6 = \ x + 6 - 6 \ = \ 5 - 6\\$ $[ \ subtracting \ by \ 6 \ ]$

$-11 = \ x \ = - 1$

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sergiy2304 [10]

Answer:

10=10

Step-by-step explanation:

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It’s 1+1 equal 11 btw I don’t know

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Find the center of the circle with the equation x2 + y2 – 6x – 4y+12 = 0.With solution.​

Find the center of the circle with the equation x2 + y2 – 6x – 4y+12 = 0.With solution.