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2 years ago

What is the equivalent to 16 to the 3/4 root

Mathematics

1 answer:

pshichka [43]2 years ago

8 0

√2x−5=7 3/4
rate if that help

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Raisins (x) that sell for $1.60 per pound are mixed with chocolate chips (y) that sell for $2.45 per pound to make 17 pounds of

Rasek [7]

Answer: B) x + y = 17

1.60x + 2.45y = 34

Step-by-step explanation:

Cost of x = $1.60 per pound

Cost of y = $2.45 per pound

Total pounds of x and y = 17

Cost per pound of mixture = $2

Total number of pounds of the mixture :

x + y = 17

Since the cost per pound of the mixture = 2

Hence ;

(Cost of x * number of pounds of x) + (Cost of y * number of pounds of y)

(1.60 * x) + (2.45 * y) = (cost per pound of mixture * total number of pounds of the mixture)

1.60x + 2.45y = 2 * 17

1.60x + 2.45y = 34

3 0

2 years ago

The Cooper family is driving 236.5 miles to visit their relatives. In the first three hours, they drive 69.4 miles in the first

Softa [21]

Answer:

29.7

Step-by-step explanation:

The remaining distance is the total distance less the distance driven so far:

... 236.5 -69.4 -67.9 -69.5 = 29.7

5 0

2 years ago

What is the slope of the line represented by the equation 10×+5y=4 a.2 b.1/2 c.-1/2 d.-2

VikaD [51]

Equation: 10x + 5y = 4
5y = -10x + 4

Divide the equation by 5,
y = -2x + 4/5

Now Compare it with, y = mx + c
Here,m = -2

In short, Your Answer would be Option D

Hope this helps!

6 0

3 years ago

A stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer. If the top laye

Svetlanka [38]

Answer: The total number of logs in the pile is 6.

Step-by-step explanation: Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two logs.

We are to find the total number of logs in the pile.

Let n represents the total number of logs in the pile.

Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with

first term, a = 32 and common difference, d = -6.

We know that

the n-th term of an arithmetic sequence with first term a and common difference d is

$a_n=a+(n-10)d.$

Since there are n logs in the pile, so we get

$a+(n-1)d=2\\\\\Rightarrow 32+(n-1)(-6)=2\\\\\Rightarrow 32-6n+6=2\\\\\Rightarrow 6n=36\\\\\Rightarrow n=6.$

Thus, the total number of logs in the pile is 6.

6 0

2 years ago

How do you solve 9 tenths minus 13 fiftenths

Elena L [17]

Answer:

0.04

Step-by-step explanation:

1. 9/10 = 0.9 and 13/15 = 0.86

2. Subtract 0.9 and 0.86

3. You should end up with 0.04

Remember when a number goes like 0.86666666666 to use 0.86 or if it has 0.86666666667 to use 0.87 because you would be simplifying it.

4 0

2 years ago