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2 years ago

Which of the following statements is not correct?

Mathematics

2 answers:

aksik [14]2 years ago

8 0

Answer:

B number 2 its incorrect chosse that one More students in the sample listed lacrosse as their

favorite sport than basketball.

Step-by-step explanation:

NeX [460]2 years ago

4 0

Answer:

The highest percentage of teenagers in the sample

listed soccer as their favorite sport.

Basketball

Lacrosse

Soccer

Football

Step-by-step explanation:

You might be interested in

The weight of a box varies directly as the volume of the box. If a 138-pound box has a volume of 23 gallons, what is the weight

kolezko [41]

Answer:

D. 150 pounds

Step-by-step explanation:

For be directly proportional, it has to be that as one value increases the other does it equally, so

If 138 pound box has a volume of 23 gallons for 25 gallons ?. For being directly proportional tha value must be higest

138 → 23 $x=\frac{25*138}{23} = 150$

x → 25

5 0

3 years ago

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

6 0

3 years ago

Please answer this correctly

MAVERICK [17]

Answer:

1:50 PM

Step-by-step explanation:

Left school at 10:38 AM,

took them 51 minutes,

38+51=89,

89-60=29,

so when they drove to the museum, it was 11:29 AM.

From here, they stayed at the museum for 1 hour and 26 minutes,

so they stayed at the museum until 12:55 AM since 29+26=55.

Now, it took them 55 minutes to drive back to the school,

so 12:55 plus another 55 minutes,

it's going to be 1:50 PM when Dale's class got back to school.

7 0

3 years ago

Mr. Weiler has 32 students in his class he wishes to place them into 8 groups of equal size. Which of the following represents t

SCORPION-xisa [38]

option 4: 4

8x4=32

hope it helps

8 0

3 years ago

Read 2 more answers

(x+5)(y+10) <br><br> what is the answer to this equation?

netineya [11]

(x + 5)(y + 10)
x(y + 10) + 5(y + 10)
x(y) + x(10) + 5(y) + 5(10)
xy + 10x + 5y + 50

7 0

2 years ago