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Artyom0805 [142]
3 years ago
5

The length of a sand volleyball court is twice its width. The perimeter is 180 feet. Find the length and width of the sand volle

yball court.
Mathematics
1 answer:
11111nata11111 [884]3 years ago
8 0
Since we know that length is twice the width, we can say that:
Perimiter = 2(twice the width) + 2(width)
Therefore, P = 2(2w) +2(w)
this simplifies to P=6w
Sine P=180, 160 = 6w, so w = 30
Because length is twice the width, length = 2 * width, or 2*30, which is 60

Therefore:
length = 60
width = 30
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This is false

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A CBS News/New York Times opinion poll asked 1,190 adults whether they would prefer balancing the federal budget over cutting ta
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Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.0166 = 1.66% probability of a sample proportion of 0.59 or less.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sampling proportions of a proportion p in a sample of size n has mean \mu = p and standard error s = \sqrt{\frac{p(1 - p)}{n}}

In this problem:

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  • In fact 62% of all adults favor balancing the budget over cutting taxes, hence p = 0.62.

The mean and the standard error are given by:

\mu = p = 0.62

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.62(0.38)}{1190}} = 0.0141

The probability of a sample proportion of 0.59 or less is the <u>p-value of Z when X = 0.59</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.59 - 0.62}{0.0141}

Z = -2.13

Z = -2.13 has a p-value of 0.0166.

0.0166 = 1.66% probability of a sample proportion of 0.59 or less.

You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213

7 0
2 years ago
An Olympic-size swimming pool holds 2,500 kiloliters of water. After swimmers splash water out of the pool, there are 24,500 hec
Kruka [31]
2,500 kiloliters = 2,500 × 10 = 25,000 hectoliters
<span>25,000 − 24,500 = </span>500<span> hectoliters</span>
5 0
3 years ago
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