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katen-ka-za [31]
3 years ago
15

Find the quadratic function y=ax^(2)+c with a graph that includes (0,1/2) (-3,73/2).

Mathematics
1 answer:
Aloiza [94]3 years ago
6 0
The answer is B.  The way you find it is through substitution. First use the coordinate (0, 1/2) in y = ax^2 + c to solve for c: 1/2=a(0)^2 + c--> 1/2=c. Now use that c value in the same y = ax^2 + c equation with the other coordinate to solve for a: 73/2 = a(-3)^2 + 1/2. Subtract 1/2 from both sides to get 72/2=9a. 72/2 is 36. So 36 = 9a...a = 4. Now fill in your a and your c to get y = 4x^2 + 1/2
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Step-by-step explanation:

yes htey are good

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2 years ago
A mass of 5 kg stretches a spring 10 cm. The mass is acted on by an external force of 10sin( t ) N(newtons) and moves in a mediu
yKpoI14uk [10]

Answer:

A) C1 = 0.00187 m = 0.187 cm,  C2 = 0.0062 m = 0.62 cm

B)  A sample of how the graph looks like is attached below ( periodic sine wave )

C) w = \sqrt[4]{3} is when the amplitude of the forced response is maximum

Step-by-step explanation:

Given data :

mass = 5kg

length of spring = 10 cm = 0.1 m

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speed of mass = 4 cm/s = 0.04 m/s

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using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion

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A) finding the solution of the initial value

attached below is the solution and

B) attached is a periodic sine wave replica of how the grapgh of the steady state solution looks like

C attached below

3 0
3 years ago
45:30
Ierofanga [76]
The answer is 50 y squared minus 4 x squared
5 0
2 years ago
Read 2 more answers
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Answer:

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3 0
3 years ago
Find the indicated area under the curve of the standard normal​ distribution; then convert it to a percentage and fill in the bl
galben [10]

Answer:

95%

Step-by-step explanation:

About 95% of the area is within two standard deviation in standard normal distribution. This can be explained by finding the probability within 2 standard deviation using standard normal distribution.

P(z1<Z<z2)=P(-2<Z<2)

P(-2<Z<2)=P(-2<Z<0)+P(0<Z<2)

P(-2<Z<2)=0.4772+0.4772

P(-2<Z<2)=0.9544

Thus, About 95% of the area is between z2 and z2

4 0
3 years ago
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