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Ber [7]
3 years ago
7

Please help me!!!! precalc question

Mathematics
1 answer:
dangina [55]3 years ago
7 0

Step-by-step explanation:

1. Ampltiude is 1

The period is

\frac{2\pi}{3}

is the period

The phase shift is 0

2. The Ampltiude is 2

The period is 2 pi

The phase shift is 1

3. The amplitude is 3

The period is 2 pi/3

The phase shift is -2

4.The amplitude is 2/3

The period is -10pi

The phase shift is 0

5. The Ampltiude is 1

The period is -2 pi

The phase shift is pi

6. The amplitude is 1/4

The period is -4pi

The phase shift is negative 2pi/3

7. The Ampltiude is 3

The period is 4

The phase shift is 8

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Solve for x! Please help!
erica [24]

Answer:

<h2>x = 12</h2>

Step-by-step explanation:

ΔADC and ΔCDB are similar (AA). Therefore the sides are in proportion:

\dfrac{AD}{DC}=\dfrac{DC}{DB}

We have AD = 16, DC = x, DB = 9. Substitute:

\dfrac{16}{x}=\dfrac{x}{9}            <em>cross multiply</em>

x^2=(16)(9)\to x=\sqrt{(16)(9)}\\\\x=\sqrt{16}\cdot\sqrt9\\\\x=4\cdot3\\\\x=12

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3 years ago
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I hope that helps!


I am with you if you faced any difficulties!






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