Answer:
The acceleration of body is given 16.3m/s2 and the force is given 4.6 N
Force=mass * acceleration
Mass=force/acceleration
So, the mass=4.6/16.3
Therefore the answer is, 0.28kg
Explanation:
A. after the carboniferous period
Answer:

Explanation:
The increase rate of population is described by the following ordinary differential equation is:

Where
is the time constant. The solution of the differential equation is:

The time constant in years is found by substituting known variables:



The doubling time is:



Answer:
16th day cause it two times every day, so half of it is always da day before it!
Really hope I helped!