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3 years ago

6

I need help with this problem please

1 answer:

NNADVOKAT [17]3 years ago

7 0

<em>n</em> must be 0, since <em>x </em>ⁿ = 1 for all positive, real <em>x</em> if <em>n</em> = 0. So the answer is A.

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-1/4x+2y=28 find the x and y intercept

Advocard [28]

The y intercept is (0, 14) and the x intercept is (-112,0) all you have to do is just make y zero if you are trying to solve for x and the same for the x if you are trying to solve for y.

8 0

4 years ago

The following results come from two independent random samples taken of two populations.

photoshop1234 [79]

Answer:

$(a)\ \bar x_1 - \bar x_2 = 2.0$

$(b)\ CI =(1.0542,2.9458)$

$(c)\ CI = (0.8730,2.1270)$

Step-by-step explanation:

Given

$n_1 = 60$ $n_2 = 35$

$\bar x_1 = 13.6$ $\bar x_2 = 11.6$

$\sigma_1 = 2.1$ $\sigma_2 = 3$

Solving (a): Point estimate of difference of mean

This is calculated as: $\bar x_1 - \bar x_2$

$\bar x_1 - \bar x_2 = 13.6 - 11.6$

$\bar x_1 - \bar x_2 = 2.0$

Solving (b): 90% confidence interval

We have:

$c = 90\%$

$c = 0.90$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.90$

$\alpha = 0.10$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.10/2}$

$z_{\alpha/2} = z_{0.05}$

The z score is:

$z_{\alpha/2} = z_{0.05} =1.645$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.645 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.645 * \sqrt{0.3306}$

$2.0 \± 0.9458$

Split

$(2.0 - 0.9458) \to (2.0 + 0.9458)$

$(1.0542) \to (2.9458)$

Hence, the 90% confidence interval is:

$CI =(1.0542,2.9458)$

Solving (c): 95% confidence interval

We have:

$c = 95\%$

$c = 0.95$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.95$

$\alpha = 0.05$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.05/2}$

$z_{\alpha/2} = z_{0.025}$

The z score is:

$z_{\alpha/2} = z_{0.025} =1.96$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.96 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.96* \sqrt{0.3306}$

$2.0 \± 1.1270$

Split

$(2.0 - 1.1270) \to (2.0 + 1.1270)$

$(0.8730) \to (2.1270)$

Hence, the 95% confidence interval is:

$CI = (0.8730,2.1270)$

8 0

3 years ago

What are the possible values of remainder r, when a positive integer 'a' is divided by 3

fredd [130]

Answer:

0, 1, 2

Step-by-step explanation:

Euclid's division Lemma states that for any two positive integers ‘a’ and ‘b’ there exist two unique whole numbers ‘q’ and ‘r’ such that , a = bq + r, where 0≤ r < b.

Here, a= Dividend, b= Divisor, q= quotient and r = Remainder.

According to Euclid's division lemma a 3q+r, where 0≤r≤3 and r is an integer.

Therefore, the values of r can be 0, 1 or 2.

6 0

3 years ago

40 POINTS. When they form conical piles, granular materials such as salt, gravel, and sand settle at different "angles of repose

grandymaker [24]

Answer:

34.0 degrees, 29.6 feet in Diameter.

This is a right triangle trigonometry question.

Use half of the diameter to form the base of the triangle (19.3 ft) with a height 0f 13.

Use Inverse Tangent function to find the angle of repose

round to 34.0

then use the angle of repose to solve trigonometric function of the tangent for the radius of the other cone.

switch denominator and tangent

multiply by 2 to get diameter of second cone

14.82*2≈29.6

hopefully this helps!

7 0

3 years ago

you can finish 1 fifth of your homework in 2 minutes . how long will it take you to finish all of it ?

Furkat [3]

10 minutes it will take you 10 minutes 10 minutes it will take you 10 minutes

7 0

4 years ago