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3 years ago

Area 10 points plz h

Mathematics

1 answer:

Sedaia [141]3 years ago

3 0

Answer:

The triangle area equals to 190 ft :)

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6. Does the set of ordered

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2 years ago

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Ksivusya [100]

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3 years ago

Read 2 more answers

Stephon has a square brick patio. He wants to reduce the width by 4 feet and increase the length by 4 feet.

alekssr [168]

Answer: The expressions for the length and width of the new patio are

$\ell=x+4,~~w=x-4.$

And the area of the new patio is 384 sq. feet.

Step-by-step explanation: Given that Stephen has a square brick patio. He wants to reduce the width by 4 feet and increase the length by 4 feet.

The length of one side of the square patio is represented by x.

We are to write the expressions for the length and width of the new patio and then to find the area of the new patio if the original patio measures 20 feet by 20 feet.

Since Stephen wants to reduce width of the patio by 4 feet, so the width of the new patio will be

$w=(x-4)~\textup{feet}.$

The length of the patio is increased by 4 feet, so the length of the new patio will be

$\ell=(x+4)~\textup{feet}.$

Now, if the original patio measures 20 feet by 20 feet, then we must have

$w=x-4=20-4=16~\textup{feet}$

and

$\ell=x+4=20+4=24~\textup{feet}.$

Therefore, the area of the new patio is given by

$A_n=\ell \times w=24\times16=384~\textup{sq. feet}.$

Thus, the expressions for the length and width of the new patio are

$\ell=x+4,~~w=x-4.$

And the area of the new patio is 384 sq. feet.

4 0

3 years ago

greyhounds can reach speeds of 20.1 meters per second. which conversion factor can be used to find this speed in meters per minu

Allisa [31]

Multiply by 60, there are 60 seconds in a minute. It would be 1206 meters/minute

4 0

3 years ago

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 L of a dyesolution with a c

nordsb [41]

Answer:

Time,t that it will elapse before the concerntration of the dye in the tank reaches1% of its original value is 460.52 seconds

Step-by-step explanation:

Let Q(t) = amount of dye for all time,t.

Let Q'= rate in - rate out.

But Q/200 = concerntration of dye

Therefore rate out= Q/200 ×2.

Q'/Q = - 1/100

Dividing by Q gives

Ln/Q/ + c = -1/100t + c1

Integrating both sides with respect to t

Ln/Q/ = -1/100t + c2.

c1 and c1 are just another constants

Q= c3e^-t/100

Exponentiating both sides will cause the absolute values to get absorbed into the constants giving rise to a new constant c3

200= c3-0/100

c3= 200

2= 200e^-t/100

Ln1/100= - t/100

Ln0.01 = - t/ 100

Cross multiply

t= Ln0.01 × 100

t = 4.6052 ×100

t = 460.52seconds

7 0

3 years ago