Answer: b. 8.56 to 21.44
Step-by-step explanation:
Let
be the mean number of pushups that can be done.
As per given , we have
Sample size : n= 10
Degree of freedom = n-1=9
Sample mean : 
Sample standard deviation : 
Significance level : α=1-0.95=0.05
From t- distribution table ,
Critical two -tailed t-value for α=0.05 and df = 9 is

Confidence interval for
is given by :-


Hence, the 95% confidence interval for the true mean number of pushups that can be done is 8.56 to 21.44.
Answer:

Step-by-step explanation:


~
Substitute ''x'' with '2' & 'y' with "-4":-

First let's solve 


Calculate exponents:- -4^5= -1024

Remove parentheses, apply rule:- 


Apply fraction rule:-


Divide numbers:-

Now that we're done factoring the denominator let's bring down the numerator which is ' 1 ':-

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Answer:
1.84
Step-by-step explanation:
So first we can do 5/7 which equals 0.714286
add 2 to that and get: 2.714286
So 5 / 2.714286 = 1.8421
Suppose the integers are n , n+2 , n+4 and n+6.
84=n+(n+2)+(n+4)+(n+6)=4n+12.
Subtract 12 from both ends to get.
72=4n.
Divide both ends by 4 to get.
n=18.
So the integers are: 18 , 20 , 22 , 24.