Answer:
99.73% of bags contain between 62 and 86 chips .
Step-by-step explanation:
We are given that the number of chips in a bag is normally distributed with a mean of 74 and a standard deviation of 4.
Let X = percent of bags containing chips
So, X ~ N(
)
The standard normal z score distribution is given by;
Z =
~ N(0,1)
So, percent of bags contain between 62 and 86 chips is given by;
P(62 < X < 86) = P(X < 86) - P(X <= 62)
P(X < 86) = P(
<
) = P(Z < 3) = 0.99865 {using z table}
P(X <= 62) = P(
<=
) = P(Z <= -3) = 1 - P(Z < 3)= 1 - 0.99865 = 0.00135
So, P(62 < X < 86) = 0.99865 - 0.00135 = 0.9973 or 99.73%
Therefore, 99.73% of bags contain between 62 and 86 chips .
The total of the inside angles for a 6 sides shape is 720 degrees.
Find the total of the known angles and subtract the from 720:
130 + 120 + 145 + 160 + 65 = 620
X = 720 - 620
X = 100
I think she is 53. 12 times 4 is 48 + 5 = 53.
Answer:
x = 65
Step-by-step explanation:
x = √(25×(25+144))
x = √(25×169)
x = 5×13
x = 65
Answered by GAUTHMATH