A sample of 100 independent random numbers is taken from this distribution, and its average is used to estimate the mean of the
1 answer:
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Answer: 32°
Step-by-step explanation: see photo
Answer:
There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.
The needed function is
Step-by-step explanation:
Let us assume the piece of paper James decides to fold is a SQUARE.
Now, let us assume:
n : the number of times the paper is folded.
y : The number of parts obtained after folds.
Now, if the paper if folded ONCE ⇒ n = 1
Also, when the pap er is folded once, the parts obtained are TWO equal parts.
⇒ for n = 1 , y = 2 ..... (1)
Similarly, if the paper if folded TWICE ⇒ n = 2
Also, when the paper is folded twice, the parts obtained are FOUR equal parts.
⇒ for n = 2 , y = 4 ..... (2)
⇒
Continuing the same way, if the paper is folded SEVEN times ⇒ n = 7
So,
⇒ There are total 128 equal parts.
Lastly, if the paper is folded ELEVEN times ⇒ n = 11
So,
⇒ There are total 2048 equal parts.
Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.
And the needed function is
Answer:(1) The correct option is b. (2) The correct option is c.
Explanation:
(1)
It is given that the △ABD≅△FEC.
So by (CPCTC) corresponding parts of congruent triangles are congruent.
It is given that the angle DAB is 63 degree.
Therefore, the correct option is b.
(2)
It is given that the △ABD≅△FEC.
So by (CPCTC) corresponding parts of congruent triangles are congruent.
Therefore, the correct option is c.