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3 years ago

CAN SOMEONE HELP ME PLS I GIVE POINTS

Mathematics

1 answer:

kogti [31]2 years ago

4 0

Answer:

and i think its b

Step-by-step explanation:

i cnt see the question and its blurry and can i get the crown thing

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64/72 in simplest form

Stells [14]

64=2^6, 72=2^3*3^2

gcd (64,72)=8
Therefore 64/8 =8
72/8=9
gcd (8,9) =1
8,9 are relatively prime.
Thus, 64/72=8/9

4 0

3 years ago

Given that ∠Ф = 180°, determine the numerical value of this function.

Rudiy27

Answer:

The answer to your question is 3. 0

Step-by-step explanation:

For an angle of 180°:

- hypotenuse = 1

- Adjacent side = 1

- Opposite side = 0

Then, sin Ф = $\frac{Opposite side}{Hypotenuse}$

sin 180° = $\frac{0}{1}$

sin 180° = 0

8 0

3 years ago

38. What is the solution to 2(x - 6) = 14?

ivanzaharov [21]

Answer:

x=13, 16(x-1)

Step-by-step explanation:

For 38, you have to first divide both sides by 2.

This becomes, x-6=7

Add 6 to both sides

x=13.

For 40. You can can distribute the 8.

This makes it 16x-16.

With this you can than, factor out the 16.

16(x-1).

5 0

4 years ago

Read 2 more answers

What’s 4 divided by 3.3

lilavasa [31]

Answer:

it is 1.21repeated hope this helps

7 0

3 years ago

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Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh

yuradex [85]

Answer:

The northern lighthouse is approximately $24.4\; \rm mi$ closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as $\rm N$ , the southern lighthouse as $\rm S$ , and the boat as $\rm B$ . These three points would form a triangle.

It is given that two of the angles of this triangle measure $40^{\circ}$ (northern lighthouse, $\angle {\rm N}$ ) and $21^{\circ}$ (southern lighthouse $\angle {\rm S}$ ), respectively. The three angles of any triangle add up to $180^{\circ}$ . Therefore, the third angle of this triangle would measure $180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ}$ (boat $\angle {\rm B}$ .)

It is also given that the length between the two lighthouses (length of $\rm NS$ ) is $75\; \rm mi$ .

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, $\angle {\rm B}$ is opposite to side $\rm NS$ , whereas $\angle {\rm S}$ is opposite to side ${\rm NB}$ . Therefore:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}$ .

Substitute in the known measurements:

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}$ .

Rearrange and solve for the length of $\rm NB$ :

$\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}$ .

(Round to at least one more decimal places than the values in the choices.)

Likewise, with $\angle {\rm N}$ is opposite to side ${\rm SB}$ , the following would also hold:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}$ .

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}$ .

$\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}$ .

In other words, the distance between the northern lighthouse and the boat is approximately $30.73\; \rm mi$ , whereas the distance between the southern lighthouse and the boat is approximately $55.12\; \rm mi$ . Hence the conclusion.

4 0

3 years ago