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Semenov [28]
3 years ago
14

PLEASE HELP!!!!!!!!!!!!!

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0
4y^2+2=(4y\cdot4y)+2\\
4y^2+2=16y^2+2 \leftarrow \text{not identity}\\\\
4y^2+2=(4y+y)+2\\
4y^2+2=5y+2 \leftarrow \text{not identity}\\\\
4y^2+2=4(y+y)+2\\
4y^2+2=8y+2 \leftarrow \text{not identity}\\\\
4y^2+2=4(y\cdot y)+2\\
4y^2+2=4y^2+2 \leftarrow \text{identity}

So it's D.
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Construct 3 linear equation starting with qiven solution z = 1/3
Andreyy89

Answer:

(a)9z+2=5

(b)21z-11=-4

(c)4z=2-2z

Step-by-step explanation:

We are required to construct 3 linear equations starting with the given solution z = 1/3.

<u>Equation 1</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 9

9z=\frac{1}{3}\times 9\\9z=3

Rewrite 3 as 5-2

9z=5-2

Add 2 to both sides

Our first equation is: 9z+2=5

<u>Equation 2</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 21

21z=\frac{1}{3}\times 21\\21z=7

Rewrite 7 as 11-4

21z=11-4

Subtract 11 from both sides

Our second equation is: 21z-11=-4

<u>Equation 3</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 6

6z=\frac{1}{3}\times 6\\6z=2

Rewrite 6z as 4z+2z

4z+2z=2

Subtract 2z from both sides

Our third equation is: 4z=2-2z

4 0
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