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3 years ago

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Subtract 1 from the product of 4 and 2. what is this in fraction form? please help? A 4 ÷ 2 − 1 B 4 × 2 − 1 C 4 × (1 − 2) D 1 −

(4 × 2)

1 answer:

Lapatulllka [165]3 years ago

3 0

Answer:

D.) 1 - (4 * 2)

Step-by-step explanation:

Given :

Product of 4 and 2 is written as : 4 * 2

Subtracting 1 from the product above : 1 - (4 *2)

Hence, the fractional form of the question above is simply written as :

1 - (4 * 2)

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Express 29.5 as a rational number

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Answer:

Step-by-step explanation:

29.5 ÷ 5 = 5.9

Therefor its an irrational number

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29.5 ÷ 100 = 0.295

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True or false<br><br> Based on the information in the diagram abc ≅ def

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Five whole numbers have the following properties: the range is 9• the

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9,11,8,8,8,8,8,8,8,8,8,8,7,8,8,8,8,8,8

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Write the sum of the numbers as the product of their GCF and another sum. Include work if possible.

trasher [3.6K]

It <span> looks like the first thing you have to find is their GCF, ya reckon ?</span>

The factors of 56 are 1, 2, 4, 7, 8, 13, 28, and 56 .

The factors of 64 are 1, 2, 4, 8, 16, 32, and 64 .

The common factors are 1, 2, 4, and 8 .

The greatest one is 8 .

56/8 = 7
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56 plus 64 = (8 times 7) plus (8 times 8)

<span>56 plus 64 = </span>8 times (7 plus 8)<span> <== that's the answer</span>

Check it out:

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Find all relative extrema of the function. Use the Second Derivative Test where applicable. (If an answer does not exist, enter

Lapatulllka [165]

Answer:

Relative minimum: $\left(-\frac{5}{2}, -\frac{33}{4}\right)$ , Relative maximum: $DNE$

Step-by-step explanation:

First, we obtain the First and Second Derivatives of the polynomic function:

First Derivative

$f'(x) = 2\cdot x + 5$ (1)

Second Derivative

$f''(x) = 2$ (2)

Now, we proceed with the First Derivative Test on (1):

$2\cdot x + 5 = 0$

$x = -\frac{5}{2}$

The critical point is $-\frac{5}{2}$ .

As the second derivative is a constant function, we know that critical point leads to a minimum by Second Derivative Test, since $f\left(-\frac{5}{2}\right) > 0$ .

Lastly, we find the remaining component associated with the critical point by direct evaluation of the function:

$f\left(-\frac{5}{2} \right) = \left(-\frac{5}{2} \right)^{2} + 5\cdot \left(-\frac{5}{2} \right) - 2$

$f\left(-\frac{5}{2} \right) = -\frac{33}{4}$

There are relative maxima.

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