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Aneli [31]
3 years ago
13

Using the triangle diagram below in the rules for special right triangles, discover the four missing links and choose them from

the available choices:

Mathematics
1 answer:
Nady [450]3 years ago
7 0

Answer:

The solution for the system of right triangles are, respectively: a = 2\sqrt{6}, b = 4\sqrt{3}, c = 4\sqrt{6}, d = 6\sqrt{2}

Step-by-step explanation:

By Geometry, we get the following equivalencies:

a = 2\sqrt{6} (45 - 45 - 90 Theorem)

b = \sqrt{2}\cdot (2\sqrt{6}) (45 - 45 - 90 Theorem)

b = 4\sqrt{3}

c = \frac{2\sqrt{6}}{\frac{1}{2} } (30 - 60 - 90 Theorem)

c = 4\sqrt{6}

d = \frac{2\sqrt{6}}{\frac{\sqrt{3}}{3} } (30 - 60 - 90 Theorem)

d = 6\sqrt{2}

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3 years ago
Is this correct and if not how do I solve quickkkkkk!!!!!
noname [10]

Answer:

29 m

Step-by-step explanation:

The dashes mean that the lines are equal in length, so from this we can determine that the area marked 441 m² is a square.  

Area of a square = x², where x is the length of 1 side.  

Therefore, x = √441 = 21 m

Now we have a right-angled triangle with two legs of 20 m and 21 m.  We need to find the hypotenuse (labelled ?).  To do this, use Pythagoras' Theorem a² + b² = c², where a and b are the legs and c is the hypotenuse.

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    20² + 21² = c²

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⇒               c = 29

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3 years ago
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A manufacturing machine has a 10% defect rate.If 4 items are chosen at random, what is the probability that at least one will ha
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Solution

Step 1

\begin{gathered} probability\text{ of defective p = 10\% = }\frac{10}{100}\text{ = 0.1} \\  \\ probability\text{ of not defective q = 1 - p = 1 - 0.1 = 0.9} \\  \end{gathered}

Step2

The probability that at least one will have a defect

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Step 3

Use the binomial distribution

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2 years ago
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