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user100 [1]
2 years ago
11

URGENT! 40 POINTS! PLEASE HELP!

Mathematics
2 answers:
MariettaO [177]2 years ago
8 0

Answer:

A and C

Step-by-step explanation:

umka2103 [35]2 years ago
4 0

Answer:

(a) 8 x(5 x-6)=40 x^{2}-48 x

(c) \begin{aligned}(x-3)(5 x-6) &=5 x^{2}-21 x+18\end{aligned}

Step-by-step explanation:

(a) To find verify the answer we need to multiplying the equation 8 x(5 x-6)

8 x(5 x-6)=40 x^{2}-48 x

Thus, this statement is true.

(b) To find verify the answer we need to multiplying the equation -4 x\left(2 x^{2}+1\right)

-4 x\left(2 x^{2}+1\right)=-8 x^{3}-4 x

Hence, the given statement is false.

(c) To find verify the answer we need to multiplying the equation (x-3)(5 x-6)

\begin{aligned}(x-3)(5 x-6) &=5 x^{2}-6 x-15 x+18 \\&=5 x^{2}-21 x+18\end{aligned}

Hence, the given statement is true.

(d) To find verify the answer we need to multiplying the equation(2 x+3)\left(x^{2}+3 x-5\right)

\begin{aligned}=(2 x+3)\left(x^{2}+3 x-5\right) &=2 x^{3}+6 x^{2}-10 x+3 x^{2}+9 x-15 \\&=2 x^{3}+9 x^{2}-x-15\end{aligned}

Hence, the given statement is false.

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A polynomial expression is shown below.
tester [92]
The polynomial is (mx^3+3)(2x²+5x+2)-(8x^5 +20x^4)
if it is reduced to 8x^3+6x²+15x+6, so we can find the value of m

 (mx^3+3)(2x²+5x+2)-(8x^5+20x^4) = <span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3+6x²+15x+6-8x^5-20x^4=<span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3=8x^3+6x²+15x+6-6x²-15x-6+ <span>8x^5+20x^4
</span>=  8x^5+20x^4+<span>8x^3= 4(2x^5+5x^4+2x^3)
finally

</span>m(2x^5+5x^4+2x^3)=<span>4(2x^5+5x^4+2x^3), and after simplification
</span>
C:  m=4

<span>4. When the expression is factored x²-3x-18 completely, 
</span>
one of its factor is x-6
<span>x²-3x-18=0
</span>D= 9-4(-18)= 81, sqrtD=9 x=3-9/2= -6/2= -3, and x=3+9 / 2= 6
so <span>x²-3x-18= (x-6)(x+6)

</span>
3 0
2 years ago
(-2, 2), y=3x - 5 distance​
Andrews [41]

Answer:

If you are using slope intercept it is incorrect

Step-by-step explanation:

For the first part y is 2 so using y=Mx+b it’s 2=-6-5 which is not correct

7 0
3 years ago
Eleanor was curious if triangles DEF and GHI were similar, so he tried to map one figure onto the other using rigid transformati
Fiesta28 [93]

Answer:B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
If f(x)=1/6x+12, then f^-1(x)=<br> PLEASE HELP
Finger [1]

f(x)=\dfrac{1}{6}x+12\to y=\dfrac{1}{6}x+12


Change x to y, and y to x.


x=\dfrac{1}{6}y+12


solve for y:


\dfrac{1}{6}y+12=x\ \ \ |-12\\\\\dfrac{1}{6}y=x-12\ \ \ \ |\cdot6\\\\y=6x-72


Your answer is:


f^{-1}(x)=6x-72

5 0
2 years ago
Given h(x) = -5x + 3, find h(5).
cluponka [151]

Answer:

h(5) = -22

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

h(x) = -5x + 3

h(5) is x = 5

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em> [Function]:                                                                                h(5) = -5(5) + 3
  2. Multiply:                                                                                                             h(5) = -25 + 3
  3. Add:                                                                                                                   h(5) = -22
8 0
2 years ago
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