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Elza [17]
3 years ago
15

Isaiah is having his house painted. He paid $525 for the required materials, and he will pay $30 an hour for the painters to com

plete the job. Which equation shows the relationship between y, the number of hours the painters work, and x, the total cost of the project?
A. y = 525x + 30
B. y = 30x - 525
C. y= 30x + 525
D. y = 525x + 30
Mathematics
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

Step-by-step explanation:

x is the amount of hours it will take. Since he pays $30 per hour, your answer would be 30x + 525

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Answer:

169.12

Step-by-step explanation:

I hope this is correct. First, you want to divide the semi-circle and the rectangle. To find the area of the rectangle, you do 16 x 9 to get 144. To find the area of the semi-circle, you do 3.14x16/2 to get 25.12. Then you want to add 144 and 25.12 to get 169.12. I hope this helps

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Calculate the mean, median, mode, range, and 5 Number Summary of the following data set: 5,6,8,4,7,5,4,2,5,6,5,2,1,4
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Answer:

mean = 4.57, median = 5 , mode = 5, range =7 ,

five number summary: Minimum value= 1 , First Quartile = 4, Median = 5

Third Quartile  = 6, Maximum value = 8

Step-by-step explanation:

First arrange the data in ascending order.

1,2,2,4,4,4,5,5,5,5,6,6,7,8

Mean = sum of all numbers / total numbers

         = 1+2+2+4+4+4+5+5+5+5+6+6+7+8 / 14

         = 64 / 14

         = 4.57

Median:

Since the given data is even number so, we can find median by taking mean of 2 middle numbers.

so the middle numbers are 7th and 8th  data i.e, 5 and 5

Median =(5+5)/2

           = 5

Mode:

The most repetitive number in the data set is mode

So Mode = 5

Range:

Range can be found by subtracting smallest number from largest number in the data set.

Smallest number  = 1, Largest number = 8

Range= Largest number - Smallest number

        = 8-1 = 7

Five no Summary

Minimum value= 1

First Quartile ( 25 % mark )= 4

Median = 5

Third Quartile (75 % mark) = 6

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First quartile can be found by : consider the data on left of the median and find median among them

Third quartile can be found by:  consider the data on right of the median and find median among them

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