Option A is correct.
If we evaluate the function at
, i.e. at the beginning, we have

with each minute, you multiply the current number of cell by 2, so they double every minute.
Option B is incorrect, because if the number of cells increases by 2 every minute, the function would be

Option C is incorrect, because after one minute (i.e. when x=1) we have

cells, so 75 is not the number of cells after one minute
Option D is incorrect in both the initial value and the behaviour of the function