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Ugo [173]
3 years ago
10

Please help me that’s would be great and I promise to mark brainlest!!

Mathematics
1 answer:
defon3 years ago
6 0

Option A is correct.

If we evaluate the function at x=0, i.e. at the beginning, we have

f(0)=75 \cdot 2^0 = 75 \cdot 1 = 75

with each minute, you multiply the current number of cell by 2, so they double every minute.

Option B is incorrect, because if the number of cells increases by 2 every minute, the function would be

f(x) = 75 + 2k

Option C is incorrect, because after one minute (i.e. when x=1) we have

f(1) = 75\cdot 2^1 = 75 \cdot 2 = 150

cells, so 75 is not the number of cells after one minute

Option D is incorrect in both the initial value and the behaviour of the function

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Step-by-step explanation:

When a=c and b=c, a=b

A would be 16+43

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Which expression is equivalent to
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Step:

* To raise a power to another power, multiply the exponents. Multiply 1/2 and −2 to get −1.

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If I had three dollars and my mom
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A girl starts to walk to her school, which is 20 miles away, at 6:50 and at a rate of 3 miles per hour. After a while, her dad p
Alexeev081 [22]

The girl walked a distance of \boxed{{\mathbf{5 miles}}}  in her way.

Further explanation:

The time can be calculated as,

{\text{ time}}=\frac{{{\text{distance}}}}{{{\text{speed}}}}  

Given:

It is given that a girl stands 20 miles away from the school at 6:50{\text{ am}}  and she started walking at the rate of 3{\text{ mi/hr}}  and then after some time her dad pick up and he drives at the rate of 30{\text{ mi/hr}} . They reach the school at 9:00{\text{ am}} .

Step by step explanation:

Step 1:

Consider x  as the distance she walked in her way.

The speed of the girl when she walked is 3{\text{ mi/hr}} .

Now use the formula of time to obtain the walk time.

\begin{gathered}{\text{ walktime}}=\frac{{{\text{distance walked}}}}{{{\text{walking speed}}}}\hfill\\{\text{ walktime}}=\frac{x}{3}\hfill\\\end{gathered}

Since the total distance is 20{\text{ miles}} .

Then consider 20-x  as the distance driven by the car.

The driving speed is 30{\text{ mi/hr}} .

Now use the formula of time to obtain the drive time.

\begin{gathered}{\text{drive time}}=\frac{{{\text{distance travelled by car }}}}{{{\text{ speed of car}}}}\hfill\\{\text{drive time}}=\frac{{20-x}}{{30}} \hfill\\\end{gathered}

Step 2:

Now we calculate the total time took by girl to reach the school.

  9:00-6:50={\text{2 hrs 10 min}}

Now convert the timing into hours as,

\begin{aligned}2{\text{ hours 10 minutes}}&=2+\frac{{10}}{{60}}\\&=2\frac{1}{6}\\&=\frac{{13}}{6}{\text{ hrs}}\\\end{aligned}

Step 3:

Total time is the sum of drive time and walk time.

The total time can be expressed as,

\frac{x}{3}+\frac{{20-x}}{{30}}=\frac{{13}}{6}

Now solve the above equation by cross multiply method.

\begin{aligned}\frac{x}{3}+\frac{{20-x}}{{30}}&=\frac{{13}}{6}\hfill\\\frac{{10x+20-x}}{{30}}&=\frac{{13}}{6}\hfill\\\frac{{9x+20}}{{30}}&=\frac{{13}}{6}\hfill\\6\left({9x+20}\right)&=13\left({30}\right)\hfill\\\end{aligned}

Now simplify the further equation.

\begin{aligned}6\left({9x+20}\right)&=13\left({30}\right)\hfill\\54x+120&=390\hfill\\54x&=390-120\hfill\\54x&=270\hfill\\\end{aligned}

Simplify the further equation.

\begin{aligned}54x&=270\hfill\\x&=\frac{{270}}{{54}}\hfill\\x&=\frac{{45}}{9}\hfill\\x&=5\hfill\\\end{gathered}

Therefore, the girl walked 5 miles.

Learn more:  

  • Learn more about the distance between the points <u>brainly.com/question/6278187 </u>
  • Learn more about the equivalent fraction <u>brainly.com/question/952259 </u>
  • Learn more about midpoint of the segment <u>brainly.com/question/3269852 </u>

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Speed, distance and time

Keywords: girl, distance, drive, walk, drive time, dad, speed, travelled, formula, cross multiply, fraction, number, multiply, addition, subtraction, equation, school

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{(4z-7,z-4,z) |z is any real number} z=-5
weeeeeb [17]

The set when z = -5 is {-27, -9, -5}

<h3>How to determine the set elements?</h3>

The set is given as:

{(4z-7,z-4,z) |z is any real number}

When z=-5, we have:

4z - 7 = 4(-5) - 7 = -27

z - 4 = -5 - 4 = -9

z = -5

So, we have:

{(4z-7,z-4,z) |z is any real number} ⇒ {-27, -9, -5}

Hence, the set when z = -5 is {-27, -9, -5}

Read more about sets at:

brainly.com/question/8053622

#SPJ1

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