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defon
2 years ago
11

What is the following quotient? StartFraction 3 StartRoot 8 EndRoot Over 4 StartRoot 6 EndRoot EndFraction.

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
7 0

You can simplify the given expression by taking out those factors who are perfect squares.

The simplified form  of the given expression will be  \dfrac{\sqrt{3}}{2}

<h3>How to simplify values which are under the root?</h3>

If possible, try to defactor what is inside the root.

For example, if 8 is under square root, then you can defactor 8 as made up of 2 times 2 times 2. Since 2 times 2 is perfect square, thus this can come out of the root.

Simply, some more such methods can be used to simplify these type of values.

<h3>Using the simplification method on given expression</h3>

\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{3\sqrt{2 \times 2 \times 2}}{4\sqrt{6}}\\\\&#10;\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{3 \times 2\sqrt{2}}{4\sqrt{6}}\\&#10;&#10;\\&#10;\dfrac{3\sqrt{8}}{4\sqrt{6}}  = \dfrac{6\sqrt{2}}{4\sqrt{6}} = \dfrac{\sqrt{6}\sqrt{2}}{4}\\\\&#10;\dfrac{3\sqrt{8}}{4\sqrt{6}}  = \dfrac{\sqrt{12}}{4} = \dfrac{\sqrt{4 \times 3}}{4} = \dfrac{\sqrt{3}}{2}

Thus, after getting simplified, the expression becomes \dfrac{\sqrt{3}}{2}

Learn more about quotient here:

brainly.com/question/16076853

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3 years ago
On a coordinate plane, square p q r s is shown. point p is at (4, 2), point q is at (8, 5), point r is at (5, 9), and point s is
Masteriza [31]

A statement which proves that the diagonals of square PQRS are perpendicular bisectors of each other is: option D.

<h3>How to calculate the slope of a line?</h3>

Mathematically, the slope of a line is given by the following formula;

Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}

For line RP, we have:

Slope = \frac{9\;-\;2}{5\;-\;4}\\\\Slope = \frac{7}{1}

Slope RP = 7.

For line SQ, we have:

Slope = \frac{6\;-\;5}{1\;-\;8}\\\\Slope = \frac{1}{-7}

Slope SQ = negative one-sevenths.

For the midpoint, we have:

In order to determine the midpoint of a line segment with two (2) endpoints, we would add each point together and divide by two (2).

Midpoint on x-coordinate = (8 + 1)/2 = 9/2 = 4.5.

Midpoint on y-coordinate = (9 + 2)/2 = 11/2 = 5.5.

In conclusion, a statement which proves that the diagonals of square PQRS are perpendicular bisectors of each other is that the midpoint of both diagonals is (4.5, 5.5), the slope of RP is 7, and the slope of SQ is negative one-sevenths.

Read more on squares here: brainly.com/question/2882032

#SPJ4

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