The simplest form of the given algebraic expression √(250c³/9d⁶) is; 5c * (√10c)]/3d³
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We are given the algebra problems as;
√(250c³/9d⁶)
Now 250c³ can be broken down into 250 = 25c² × 10c
Thus, we now have;
√(250c³/9d⁶) = [√(25c²) * (√10c)]/√9d⁶
When we breakdown the above expression, we have;
5c * (√10c)]/3d³
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Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or
ft
=
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
=
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k(
)
k = 18
Work done (W) to stretch the spring by
ft will be
W = 
= 
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9(
)²
= 7.56 lb-ft
But this is not a question. proof? no question mark
Answer:
The answer is 54 9/14
Step-by-step explanation:
what u do is this
#1. 765 divided by 14 which equals 54.64285714. Don't worry about the numbers after the decimal.
Then u do 65-54= 9 so u have 54 9/14
to check yourself just do 14 times 54= 756 + 9 = 765